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vekshin1
2 years ago
7

Select all statements that are true about the triangles.

Mathematics
1 answer:
Ratling [72]2 years ago
5 0

Answer:

Triangle ABC and BCD are congruent by the side side side triangle congruence theorem

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Solve the following equation. Determine if the equation is an "identity" or "contradiction."
Leona [35]
To solve, we must get x by itself. the first step we must take is to remove all of the parentheses. To do this, we must use distribution to multiply 5 by x - 6.

5(x - 6) = 3x - 18 + 2x

5x - 30 = 3x - 18 + 2x

Next, we must add like terms.

5x - 30 = 5x - 18

Finally, we must get x by itself. to do this, we must subtract 5x from both sides.

5x - 30 - 5x = 5x - 18 - 5x

Then, we add like terms again.

-30 = -18

Because this is a false statement, the equation is a contradiction.
8 0
4 years ago
I NEED HELP WITH THIS PLEASE AND PLEASE DONT SEND LINKS
TEA [102]

Answer:

The coins probability is 1/2 while the dice probability is 1/6

Step-by-step explanation:

The coin only has 2 sides so you split it into halves

The dice has 6 sides so you split it into sixths

6 0
3 years ago
Solve please and how would u graph the answer would it go left or right side
babunello [35]

Answer:

y<1

Step-by-step explanation:

4 0
3 years ago
What is the value of the 8 in this number...1,284,590?​
Ymorist [56]

Answer: 8 ten thousands

Explanation: To determine what the digit 8 means in 1,284,590, if we put 1,284,590 into the place value chart, we can see that the the 8 appears in the tens column of the thousands period so the digit 8 in this number means 8 ten thousands.

5 0
4 years ago
Identify the expressions for which limits exist.
Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

Limits exist for:

\lim_{x \to4 \4} \frac{x^2 -x-12}{4-x} = \frac{(x-4)(x+3)}{4-x} = ( - 1 )( x + 3 ) = - 7

\lim_{x \to \ 2} \frac{x^2 +2x-8}{2-x} = \frac{(x+4)(x-2)}{2-x} = ( - 1 )( x + 4 ) = - 6

\lim_{x \to2 } \frac{x^2 +3x - 10}{x^2 -4} = \frac{(x+5)(x-2)}{(x+2)(x-2)} = \frac{x+5}{x+2} = \frac{7}{4}

5 0
2 years ago
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