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Alisiya [41]
3 years ago
10

5(-2 -2p) simplify expression

Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0

Answer:

-10 -10p

Step-by-step explanation:

5(-2 -2p)

Distribute the 5

5*-2 +5(-2p)

-10 -10p

mylen [45]3 years ago
3 0

[ Answer ]

\boxed{-10 \ - \ 10p}

[ Explanation ]

  • Simplify: 5(-2 - 2p)

-------------------------------------------

  • Distribute

5 (-2) -5 · 2p

  • Apply Minus / Plus Rules

-5 · 2 - 5 · 2p

  • Multiply Numbers: 5 · 2 = 10

-10 - 10p

\boxed{[ \ Eclipsed \ ]}

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Samantha has chocolate bars and lollipops in the the ratio 4:5. If she has 12 chocolate bars,how many lollipops does she have?
labwork [276]
4 • 3 = 12
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8 0
2 years ago
Using the bijection rule to count binary strings with even parity.
AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

  • f(a) = a c {1} if a has an odd number of 1's
  • f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

  • If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
  • If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

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3 years ago
Select the margin of error that corresponds to the sample mean that corresponds to each population:
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4 0
3 years ago
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The line a bus arrives at the bus stop every 25 minutes, and the line b bus arrives every 15 minutes.Both are at the stop right
vova2212 [387]

Answer:

  after 75 minutes

Step-by-step explanation:

The least common multiple (LCM) of 15 and 25 is 75. It can be found a couple of ways:

1. List the factors of each number and find the product of the unique ones:

  15 = 3·5

  25 = 5²

The LCM is 3·5² = 75.

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2. Find the greatest common divisor (GCD) and divide the product of the numbers by that value. From the above list of factors, we see that 5 is the GCD of 15 and 25. Then the LCM is ...

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Or, you can simply list multiples of each number and see what the smallest number is that is in both lists:

  15, 30, 45, 60, <em>75</em>, 90

  25, 50, <em>75</em>, 100

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The two buses will appear together again after 75 minutes.

5 0
3 years ago
PLEASE HELP I NEED TO FINISH THIS!!!!! 98 POINTS!!!
muminat
1. given
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4. definition of angle bisector
5. definition of congruence
6. measure angle 1 is equal to measure angle 3
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