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3 years ago

1729 math problem which two pairs of numbers have cubes that add up to 1729

Mathematics

1 answer:

RoseWind [281]3 years ago

4 0

Where Are The Two Pairs?/ Finish The Rest Of The Question So I Can Help

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If i have 35% of a phones and its now $78 how much was the phone before the discount

denpristay [2]

Step-by-step explanation:

Multiply $78 by by 65/100 to determine the original price.

78 can be put over 1.

Multiply:

$\frac{78}{1} \times \frac{65}{100} = \frac{5070}{100}$

Simplify by dividing the numerator and denominator by 100:

$\frac{5070 \div 100}{100 \div 100} = \frac{50.70}{1}$

The original price was $50.70.

7 0

3 years ago

farmer pythagoras has three fields, but only two children. What is the easiest way for him to split the land in his fields equal

svetoff [14.1K]

Give each of the kids a full field then have them share or split the other field

7 0

3 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

3 years ago

Solve by graphing. 2x + 3y = 6 2x - 2y = -4

Lana71 [14]

Slope -2/3
Y Intercept 2

Slope1
Y Intercept 2

3 0

3 years ago

I need the answer to a parts I-iii and the answer to b

fomenos

Answer:

i) Mean = 72

ii) Median = 72

iii) Mode = 72

69, 70, 71, 72, 72, 72, 73, 74, 75

Step-by-step explanation:

a. To find mean, median and mode

It is given that all the 9 students get 72 marks.

Therefore the data set be,

72, 72, 72, 72, 72, 72, 72, 72 72

i) mean = (sum of data)/(total number of data)

= (9 * 72)/9 = 9

ii) Median - Central data in the data set when arranging ascending or descending order

72, 72, 72, 72, 72, 72, 72, 72 72

Median = 72

iii) Mode - Most repeating data in the data set

Here mode = 72

b). To find a data set

69, 70, 71, 72, 72, 72, 73, 74, 75

Here Mean, mode and median are all 72

3 0

4 years ago