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Nostrana [21]
3 years ago
12

Can you please help me with this question ​

Mathematics
1 answer:
user100 [1]3 years ago
5 0

Answer:

tbh im dumb so

Step-by-step explanation:

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The sum of 3 consecutive integers is 78. What is the integer closest to zero?
vova2212 [387]

Answer:

25

Step-by-step explanation:

Let n be the first integer.

Then the second integer will be (n + 1).

And the third will be (n + 2).

The sum is 78. Therefore:

n+(n+1)+(n+2)+78

Solve for n. Combine like terms:

3n+3=78

So:

3n=75

Therefore:

n=25

Therefore, the first integer is 25.

So our sequene is 25, 26, and 27.

The integer closest to zero will thus be 25.

5 0
2 years ago
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What is 5 x 5 in expanded form<br>​
NikAS [45]

Answer:

5×10°

Hope this helped you!!!

3 0
3 years ago
How can you add 3over 10 and 2over5
otez555 [7]

Answer:

7/10

Step-by-step explanation:

3/10+2/5

You have to make like denominators

So you multiply 2/5 by 2 since 1/ is the common denominator.

Then you add them

Hope this helped

6 0
3 years ago
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Substitute (= 3 and 1-6 to determine if the two expressions are equivalent.
mezya [45]

Answer:a b d

Step-by-step explanation:

4 0
3 years ago
Let f(x) = -3x + 2 and g(x) = 2x – 5;<br> compute g(f(x))
ki77a [65]

Answer:

g(f(x)) = -6x+6.

Step-by-step explanation:

It is given that,

f(x) = -3x + 2 and g(x) = 2x – 5

We need to find g(f(x)).

Put it into g(x).

g(f(x)) = 2(-3x + 2)+2

= -6x+4+2

=-6x+6

Hence, the value of g(f(x)) is -6x+6.

8 0
2 years ago
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