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SashulF [63]
4 years ago
8

Which relation is represented by the arrow diagram?

Mathematics
2 answers:
9966 [12]4 years ago
7 0

Answer:

the 1 one

Step-by-step explanation:

Mazyrski [523]4 years ago
6 0

Answer:

The First one

Step-by-step explanation:

-2 with zero , -1 with zero , zero with 6

etc....

from the diagram you see that.

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Please help I only have 15 minutes to complete this last one
Natalka [10]

Answer:

the slope of MN= -5-1/3-(-6)=-2/3

two lines are parallel>> slopes are equal

equation of line = (y-y'=m(x-x'))

therefore, y-1= -2/3(x-6)

y-1 = -2/3x + 4

y+2/3x=5

6 0
3 years ago
Some body please help me!!!!!!
VladimirAG [237]

Surface area of a cube = 486 square inches

Solution:

Given each side of a cube = 9 inches

Net of a cube has 6 squares.

Area of square = side × side

Area of 1 square = 9 × 9 = 81 square inches

Surface area of a cube = Area of 6 squares

                                      = 6 × (side × side)

                                      = 6 × 81

                                      = 486 square inches

Hence, surface area of a cube is 486 square inches.

7 0
4 years ago
What is the difference between arcsin and sin^-1 ?
Len [333]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2094473

_______________


Both refer to the inverse sine function.

The inverse sine (or arcsine) of x:

\mathsf{f(x)=arcsin(x)=sin^{-1}(x)}


where x is a real number in the domain of the function:

\mathsf{-1\le x\le 1}


and the arcsine function returns an angle in the interval  \mathsf{\left[-\,\frac{\pi}{2},\,\frac{\pi}{2}\right]:}

\mathsf{-\,\dfrac{\pi}{2}\le arcsin(x)\le \dfrac{\pi}{2}}\quad\longleftarrow\quad\textsf{range of the inverse sine function.}


So if you see anywhere one of these expressions below

\mathsf{\theta=arcsin(x)~~or~~\theta=sin^{-1}(x)}


then you should look for an angle \theta that satisfies the following conditions:

\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{sin\,\theta=x;} \end{array}\\\\\\
\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{\dfrac{\pi}{2} \le \theta\le\dfrac{\pi}{2}.} \end{array}


This angle \theta is called the inverse sine of the real number x.

______


Pay attention and do not mistake the arcsine function for the reciprocal of sine (which is cosecant); especially if you prefer or see that notation with an superscript -1. This one can be easily mistaken for an exponent:

\mathsf{sin^{-1}(x)=arcsin(x)\qquad\quad\checkmark}


but the reciprocal is something like

\mathsf{\big[sin(x)\big]^{-1}=\dfrac{1}{sin\,(x)}=csc(x)\qquad\quad(!!)}

and this last one has a total different meaning.


I hope this helps. =)

6 0
4 years ago
NEED HELP ASAP!!!!
Genrish500 [490]

Answer:

B) Jill omitted a factor pair, which affected the GCF and factored expression.

Step-by-step explanation:

Jill is factoring the expression 13xy-52y. Her work is shown below.  

Factors of 13xy: 1, 13, x, y  

Factors of 52y: 1, 2, 26, 52, y       OOPSIE  she forgot 4,13

GCF: y

Factored expression: y(13x-52)   13y (x-4)

4 0
4 years ago
Read 2 more answers
If the ratio of the area of two squares is 9:1 find the ratio of their perimeter
Lena [83]

Answer:

3:1

Step-by-step explanation:

area is 2D while the perimeter is a length which is 1D. you can also about this in how the area is units squared while the perimeter is just units. so we need the square roote of 9 and 1, sqrt(9) = 3, sqrt(1) = 1. so the ratio of the perimeter is 3:1

7 0
3 years ago
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