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3 years ago

Which relation is represented by the arrow diagram?

Mathematics

2 answers:

9966 [12]3 years ago

7 0

Answer:

the 1 one

Step-by-step explanation:

Mazyrski [523]3 years ago

6 0

Answer:

The First one

Step-by-step explanation:

-2 with zero , -1 with zero , zero with 6

etc....

from the diagram you see that.

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Are lines of symmetry for any given polygon also diagonal?

Vedmedyk [2.9K]

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2 years ago

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Use triangle XYZ to answer questions 3-5.

Murljashka [212]

Answer:

Step-by-step explanation:

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2 years ago

Compute the matrix of partial derivatives of the following functions.

s344n2d4d5 [400]

For a vector-valued function

$\mathbf f(\mathbf x)=\mathbf f(x_1,x_2,\ldots,x_n)=(f_1(x_1,x_2,\ldots,x_n),\ldots,f_m(x_1,x_2,\ldots,x_n))$

the matrix of partial derivatives (a.k.a. the Jacobian) is the $m\times n$ matrix in which the $(i,j)$ -th entry is the derivative of $f_i$ with respect to $x_j$ :

$D\mathbf f(\mathbf x)=\begin{bmatrix}\dfrac{\partial f_1}{\partial x_1}&\dfrac{\partial f_1}{\partial x_2}&\cdots&\dfrac{\partial f_1}{\partial x_n}\\\dfrac{\partial f_2}{\partial x_1}&\dfrac{\partial f_2}{\partial x_2}&\cdots&\dfrac{\partial f_2}{\partial x_n}\\\vdots&\vdots&\ddots&\vdots\\\dfrac{\partial f_m}{\partial x_1}&\dfrac{\partial f_m}{\partial x_2}&\cdots&\dfrac{\partial f_n}{\partial x_n}\end{bmatrix}$

So we have

(a)

$D f(x,y)=\begin{bmatrix}\dfrac{\partial(e^x)}{\partial x}&\dfrac{\partial(e^x)}{\partial y}\\\dfrac{\partial(\sin(xy))}{\partial x}&\dfrac{\partial(\sin(xy))}{\partial y}\end{bmatrix}=\begin{bmatrix}e^x&0\\y\cos(xy)&x\cos(xy)\end{bmatrix}$

(b)

$D f(x,y,z)=\begin{bmatrix}\dfrac{\partial(x-y)}{\partial x}&\dfrac{\partial(x-y)}{\partial y}&\dfrac{\partial(x-y)}{\partial z}\\\dfrac{\partial(y+z)}{\partial x}&\dfrac{\partial(y+z)}{\partial y}&\dfrac{\partial(y+z)}{\partial z}\end{bmatrix}=\begin{bmatrix}1&-1&0\\0&1&1\end{bmatrix}$

(c)

$Df(x,y)=\begin{bmatrix}y&x\\1&-1\\y&x\end{bmatrix}$

(d)

$Df(x,y,z)=\begin{bmatrix}1&0&1\\0&1&0\\1&-1&0\end{bmatrix}$

5 0

3 years ago

The total surface area if a cylindrical can, whose height is equal to the radius of the base is 2464 cm^2, find its volume.

KIM [24]

Step-by-step explanation:

TSA of cylinder = 2πr (h + r)

according to the question

height = radius

then,

TSA = 2πr (r + r)

2464=2 × 3.1415×r ×2r

2464/4 ×3.1415 = r×r

196.08 = r^2

r = 14.00

r = 1 4 cm

We know,

volume = 2πr ^2 ×h

=2×3.1415×14×14×14 (h=r)

=17240.552 cm^3

5 0

1 year ago

If the triangles in the figure are similar what is the length of side b?

kolezko [41]

Answer:

A 36

Step-by-step explanation:

We can determine the scale factor

From triangle ABC BC =9

DEF EF = 90

We multiply by 10

The scale factor is 10

AC ( 10) = DF

We know DF = 360

b * 10 = 360

Divide each side by 10

10b/10 = 360/10

b = 36

6 0

2 years ago