Question

1. A large game cube with a three inch side

Answer 1

Answer:

$540 \ in^2$

Step-by-step explanation:

Given the side of each cube is 3 in, the individual surface areas is calculate as:

$A=6s^2\\\\A=6\times 3^2\\\\A=54 \ in^2$

To find the wrap needed for 10 cubes, we multiply the surface area by 10:

$A_{10}=10\times 54 \ in^2\\\\A=540 \ in^2$

Hence, the shrink wrapped needed for the 1o cubes is 540 sq in