(2,5)(-1,8)
slope = (8 - 5) / (-1 - 2) = 3/-3 = -1
y - y1 = m(x - x1)
slope(m) = -1
(2,5)...x1 = 2 and y1 = 5
now we sub
y - 5 = -1(x - 2) <==
Well Im just guessing but 1 1/2 foot
Answer:
N/A
Step-by-step explanation:
This can't be answered, does not make sense, What percentage??
Answer:
C) P (X2 ≤ 8.2) = 0.96
Step-by-step explanation:
P value for the test is the probability of obtaining results that have been observed in the null hypothesis statement. A very small value of p indicates that there is unlikely chance of null hypothesis being true which means that we cannot accept null hypothesis based on the small p value.
Answer:
0.1971 ( approx )
Step-by-step explanation:
Let X represents the event of weighing more than 20 pounds,
Since, the binomial distribution formula is,

Where, 
Given,
The probability of weighing more than 20 pounds, p = 25% = 0.25,
⇒ The probability of not weighing more than 20 pounds, q = 1-p = 0.75
Total number of samples, n = 16,
Hence, the probability that fewer than 3 weigh more than 20 pounds,




