Hi!
Let's write it in slope intercept form first.
y = mx + b
Subtract y intercepts
1 - (-2) = 3
Subtract x intercepts
2 - (-3) = 5
y = 3/5x + b
Substitute one of the points to find y intercept.
1 = 3/5 · 2 + b
1 = 1.2 + b
-0.2 = b
y = 3/5x - 0.2
Now substitute the point (5,3), and if the equation is still correct, then it does pass through that point.
5 = 3/5 · 3 - 0.2
5 = 1.8 - 0.2
5 = 1.6
Since the equation is in correct, the line does NOT pass through the point (5,3).
Hope this helps! :)
Hey there!
This grocer is mixing two kinds of coffee. I always love the smell of coffee!
We will say that x sells for $1.15 per pound and y sells for $2.75 per pound.
Altogether there are 24 pounds of coffee he is selling.
The algebraic equation would be x + y = 24
At $1.30 per pound, he will make 24 * $1.30 = $31.2
So, how many of the x and y kinds of coffee should he use to make the $1.30 per pound mixture which will net him $31.2?
The algebraic equation would be 1.15x + 2.75y = 31.2
We now have two equations :
x+y = 24
1.15x + 2.75y = 31.2
Substituting x= 24 -y in the second equation gives us
1.15(24-y) + 2.75y = 31.2
27.6 - 1.15y + 2.75y = 31.2
27.6 + 1.6y = 31.2
1.6y = 31.2 - 27.6
0.3y= 3.6
y= 2.25
x + y = 24
x + 2.25 = 24
x = 24 -2.25
x = 21.75
If y=2.25, then x= 21.75 as well.
So, he will use 21.75 pounds of the $1.15 per/lb one and another 2.25 pounds of the $2.75per/lb one.
~Done~
Set up a ratio with height over shadow height:
40/30 = x/15
Cross multiply:
40 x 15 = 30x
600 = 30x
Divide both sides by 30:
X = 20
The tree is 20 feet tall.
<h2>
The values of the variable are 3 and 6.</h2>
Step-by-step explanation:
In parallelogram RECT is a rectangle,
EC = x + y , RT = 2x - y, RE = 2x + y and TC = 3x - 3
To find, the values of the variable = ?
∵ The opposite sides are equal.
∴ RE = TC and RT = EC
2x + y = 3x - 3
⇒ x - y = 3 .......... (1)
Also,
2x - y = x + y
⇒ x - 2y = 0 .......... (2)
Subtracting (1) from (2), we get
∴ x - y - (x - 2y ) = 3 - 0
⇒ x - y - x + 2y = 3
⇒ y = 3
Put y = 3 in equation (1), we get
x - 3 = 3
⇒ x = 3 + 3 = 6
∴ x = 6 and y = 3
Thus, the values of the variable are 3 and 6.