A triangle can be formed with sides length s 2 in, 3 in and 6 in true or false

Mathematics

1 answer:

NeX [460]3 years ago

7 0

False in a triangle 2 sides are the same and one is different

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3 lb 5 oz X 6 = __lb __ oz

hoa [83]

19lbs 14 ounces because 16 oz= 1lb

6 0

3 years ago

A study claims that the mean age of online dating service users is 40 years. Some researchers think this is not accurate and wan

Mademuasel [1]

Answer: $H_0:\mu=40$

$H_0:\neq40$

Step-by-step explanation:

A null hypothesis is a hypothesis where a researcher generally try to disprove, it says that there is no statistically significant relationship between the two variables .
An alternative hypothesis says that there is a statistical significance between two variables.

Claim 1. : Mean age of online dating service users is 40 years.

i.e. $\mu=40$ , since it has equals sign so we take this as null hypothesis.

Claim 2. : Mean age of online dating service users is not 40 years.

$\mu\neq40$

⇒ Null Hypothesis : $H_0:\mu=40$

Alternative hypothesis : $H_0:\neq40$

5 0

3 years ago

If you invest $500 at 4% interest,compounded annually,how much is in the account at the end of six years?

Genrish500 [490]

So, we'll find out how much interest this person will have in 6 years and then add it to the original deposit. To do this we will multiply all the factors:

500 x 0.04 x 6 = 120.
This means they'll have made $120 in interest in 6 years if they don't touch the money. We will add the 120 to the 500.
500+120= 620

They will have a total of $620 in their account after 6 years.

3 0

3 years ago

Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the

Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

$y=Ce^{kt}$ . We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is $\frac{dy}{dt}$ . Thus, the change in the concentration of salt is found in

$\frac{dy}{dt}=$ inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

$3(\frac{y}{400})$