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insens350 [35]
3 years ago
8

A triangle can be formed with sides length s 2 in, 3 in and 6 in true or false

Mathematics
1 answer:
NeX [460]3 years ago
7 0
False in a triangle 2 sides are the same and one is different
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what transformation occurs(vertically stretched, vertically compressed, reflection, translation, rotation, etc) happens when a f
trasher [3.6K]
<h3>Answer: reflection over x axis</h3>

g(x) = -f(x) is the same as g(x) = -1*f(x)

Since y = f(x), we are really saying g(x) = -1*y. Whatever the y coordinate is on f(x), multiply it by -1. This turns something like y = 2 into y = -2, or something like y = -3 into y = 3, etc etc. Visually this reflects the point over the horizontal x axis. Do this to all points on f(x), and the entire curve reflects over the x axis.

I show an example of y = x^2 turn into y = -x^2 in the attached image below.

8 0
3 years ago
Plz help on 12<br> Will give brainliest
liraira [26]

The sum of 2 complementary angles equals 90 degrees.


If angle 1 and 2 are complementary and angle 1 and 3 are also complementary than angle 2 would have to be the same as angle 3.


The answer would be true.

7 0
3 years ago
Ruby will buy3 ivory silk lilac trees or 2 bur oak trees. He wants to buy the trees that cost less. What trees will he buy? How
baherus [9]

Rudy will buy 3 Ivory Silk Lilac trees; $4

22 × 3 = 66; 35 × 2 = 70

$70 − $66 = $4

Hope this helped.

I got this same exact question in third grade and this was my answer.

3 0
3 years ago
OMG HELP PLS IM PANICKING OMG OMG I GOT A F IN MATH AND I ONLY HAVE 1 DAY TO CHANGE MY GRADE BECAUSE TOMORROW IS THE FINAL REPOR
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Answer:

3 tens

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6 0
3 years ago
Which of the following is a solution of x2 + 2x + 4?
ivolga24 [154]
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:

</span>x^2 + 2x + 4= 0.  "Completing the square" seems to be the easiest way to go here:

rewrite   x^2 + 2x + 4  as   x^2 + 2x + 1^2 - 1^2 = -4, or
                                              (x+1)^2 = -3
or                                            x+1 =i*(plus or minus sqrt(3))

or                                            x = -1 plus or minus i*sqrt(3)

This problem, like any other quadratic equation, has two roots.  Note that the fourth possible answer constitutes one part of the two part solution found above.
3 0
3 years ago
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