if the minute hand is 8 inches long, it shows the radius of the circle of the clock.
thus, the circumference of the circle (boundary)= 2πr
= 2X 3.14 X 8 ( wherein, r= radius= 8; π= 22/7 or 3.14)
= 50.27 inches.
The length between each two consecutive no.s on the clock = 50.27/12 = 4.19
Thus, the length moved n=by the tip of the minute hand= 4.19X8
= 33.44 inches
Hope that this would be correct .
The minute hand is like an eight inch radius of a circle, whose circumference would equal 2 * PI * 8 = 50.265 inches. By moving to 8 o'clock, it travels 2/3 of the circumference or 50.265 * 2/3 = 33.510 inches
Answer:
16
Step-by-step explanation:
Multiplecation by the length width, and the height, then divide and its 16.
91.3