If D = Z + 6 and C = -2 + Z - Z^2, find an expression that equals 3D + C in standard form

Mathematics

1 answer:

kykrilka [37]3 years ago

6 0

Answer:

4Z+16-Z²

Step-by-step explanation:

Given that,

D = Z+6

C = -2 + Z - Z²

We need to find the value of 3D+C.

So,

3D+C = 3(Z + 6)+(-2 + Z - Z²)

= 3Z+18-2+Z-Z²

= 4Z+16-Z²

So, the required expression is 4Z+16-Z².

You might be interested in

Absolote value x=6. any help

loris [4]

I can help but what is the q it doesn’t make since

7 0

4 years ago

Geometry, Triangle in a circle. Find X show work and explain please

nikklg [1K]

Answer: $x=7$

Step-by-step explanation:

By the Intersecting Secants Theorem, we know that:

$(5)(x+5)=(6)(6+4)$

Having this, we can find the value of "x" by solving for "x":

Applying Distributive property:

$(5)(x+5)=(6)(24)\\5x+25=60$

Subtract 25 from both sides of the equation:

$5x+25-25=60-25\\5x=35$

And finally dviding both sides of the equation by 5, we get:

$\frac{5x}{5}=\frac{35}{5}\\x=7$

7 0

3 years ago

What is the slope of the line shown in the graph?

n200080 [17]

$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-2}{0-(-2)}\implies \cfrac{1-2}{0+2}\implies -\cfrac{1}{2}$