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fomenos
3 years ago
13

Need help with this ​

Mathematics
2 answers:
anygoal [31]3 years ago
8 0

Answer:

It's the 3rd option.

-p^6

Step-by-step explanation:

Mrac [35]3 years ago
3 0

Answer:

The answer is -p^6

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A journalist reported that the average amount of time that a French person spends eating lunch at a restaurant is 22 minutes. Pe
maw [93]

Answer:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

t=\frac{19 -22)-(0)}{4.095\sqrt{\frac{1}{8}+\frac{1}{7}}}=-1.416

Step-by-step explanation:

Data given

American: 21,17,17,20,25,16,20,16 (Sample 1)

French: 24,18,20,28,18,29,17 (Sample 2)

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

This last one is an unbiased estimator of the common variance \sigma^2

The system of hypothesis on this case are:

Null hypothesis: \mu_1 = \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 = 0

Alternative hypothesis: \mu_1 -\mu_2 \neq 0

Our notation on this case :

n_1 =8 represent the sample size for group 1

n_2 =7 represent the sample size for group 2

\bar X_1 =19 represent the sample mean for the group 1

\bar X_2 =22 represent the sample mean for the group 2

s_1=3.117 represent the sample standard deviation for group 1

s_2=5.0 represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

S^2_p =\frac{(8-1)(3.117)^2 +(7 -1)(5.0)^2}{8 +7 -2}=16.770

And the deviation would be just the square root of the variance:

S_p=4.095

And now we can calculate the statistic:

t=\frac{19 -22)-(0)}{4.095\sqrt{\frac{1}{8}+\frac{1}{7}}}=-1.416

Now we can calculate the degrees of freedom given by:

df=8+7-2=13

And now we can calculate the p value using the altenative hypothesis:

p_v =2*P(t_{13}

So with the p value obtained and using the significance level assumed \alpha=0.1 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance we don't have significant differences between the two means.  

3 0
3 years ago
a student needs three pieces of wire for a part project the second piece must be four times as long as the first the third piece
ollegr [7]
First piece is x
second piece is y.    y=4x
third piece is z.        z=3y=12x

x+y+z=680
x+4x+12x=680
17x=680.   x=40cm   y=160cm.   z=480cm
8 0
4 years ago
This is my very first trig problem and I'd like to know how to tackle this. Please explain how I can do problems like these in t
Paha777 [63]

\tan(50°)  =  \frac{QR}{PQ} \Leftrightarrow QR = PQ \tan(50°) = 8.1 \tan(50°) \approx9.65 \\  \cos(50°)  =  \frac{PQ}{PR} \Leftrightarrow PR =  \frac{PQ}{\cos(50°)}  = \frac{8.1}{\cos(50°)} \approx12.6

5 0
3 years ago
Help with my homework
irinina [24]
The answer is B, there’s no solution.
6 0
2 years ago
What is the domain of the following quadratic equation? <br> f(x)=2x^2+5x-7
julia-pushkina [17]
Domain is th enumbers you can use and not cause conflict (like dividing by 0 or something)

actually, the domain is all real numbers
there is no real value of x that will make us divide by 0 or take the square root of a negative number

domain is all real numbers
5 0
3 years ago
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