Answer:
1.02272727... mi per hr
Step-by-step explanation:
Answer:

Step-by-step explanation:
Step 1
Find the radius of the circular cross section
we know that
The circumference is equal to

we have

substitute and solve for r

simplify


Step 2
Find the area of the circular cross section
The area of the circle is equal to

we have

substitute


Answer
∴ The true statement is Answer:
The true statement is BD ≅ CE ⇒ 3rd answer
Step-by-step explanation:
- There is a line contained points B , C , D , E
- All points are equal distance from each other
- That means the distance of BC equal the distance of CD and equal
the distance of DE
∴ BC = CD = DE
- That means the line id divided into 3 equal parts, each part is one
third the line
∴ BC = 1/3 BE
∴ CD = 1/3 BE
∴ DE = 1/3 BE
∵ BC = CD
∴ C is the mid-point of BD
∴ BC = 1/2 BD
∵ CD = DE
∴ D is the mid-point of DE
∴ CD = 1/2 CE
- Lets check the answers
* BD = one half BC is not true because BC = one half BD
* BC = one half BE is not true because BC = one third BE
* BD ≅ CE is true because
BD = BC + CD
CE = CD + DE
BC ≅ DE and CD is common
then BD ≅ CE
* BC ≅ BD is not true because BC is one half BD
∴ The true statement is BD ≅ CE
plz mark me brainliest
Answer:327
Step-by-step explanation:
20 pounds is 320 ounces and the lunch box plus that is 327 ounces
Answer:
11.2
Step-by-step explanation:
divide 160 by 14.3