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Pachacha [2.7K]
3 years ago
13

How much more is 8x10^9 than 2x10^3? example: Answer is 1x10^2

Mathematics
1 answer:
swat323 years ago
5 0

Answer: 8x10 to the power of 9 = 80000000000

2x10 to the power of 3 = 2000

And I don’t know understand why you put 1x10 to the power of 2

But 1x10 to the power of 2 =100

Step-by-step explanation: Is this kind of answer you want hope this help

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The packpack is 84% off.

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10 + 3x < 4 or 2x + 5 > 11 in interval notation​
Stella [2.4K]

Answer:

( − ∞ , ∞ ) hope i help

Step-by-step explanation:

First, solve each inequality. I'll solve the first one first.

7 ≥ 2 x − 5

12 ≥ 2 x

6 ≥ x

Therefore, x could be any number less than or equal to 6. In interval notation, this looks like:

( − ∞ , 6 ]

The parenthesis means that the lower end is not a solution, but every number above it is. (In this case, the lower end is infinity, so a parenthesis must be used, since infinity is not a real number and so it cannot be a solution.) The bracket means that the upper end is a solution. In this case, it indicates that not only could  

x

be any number less than 6, but it could also be 6.

Let's try the second example:

3 x − 2 4 > 4

3 x − 2 > 16    3 x > 18 x > 6

Therefore, x could be any number greater than 6, but x couldn't be 6, since that would make the two sides of the inequality equal. In interval notation, this looks like:

( 6 , ∞ )  

The parentheses mean that neither end of this range is included in the solution set. In this case, it indicates that neither 6 nor infinity are solutions, but every number in between 6 and infinity is a solution (that is, every real number greater than 6 is a solution).

Now, the problem used the word "OR", meaning that either of these equations could be true. That means that either  x  is on the interval  ( − ∞ , 6 ] or the interval  ( 6 , ∞ )

. In other words,  x

is either less than or equal to 6, or it is greater than 6. When you combine these two statements, it becomes clear that  

x

could be any real number, since no matter what number  

x

is, it will fall in one of these intervals. The interval "all real numbers" is written like this:

( − ∞ , ∞ )

6 0
4 years ago
If the money and interest are left in the bank how much is the total accumulated savings at the end of the second year for a sav
Mekhanik [1.2K]
\qquad \textit{Compound Interest Earned Amount}\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\qquad 
\begin{cases}
A=\textit{current amount}\\
P=\textit{original amount deposited}\to &\$3,500\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=\textit{times it compounds per year}\to &1\\
t=years\to &2
\end{cases}
\\ \quad \\
A=3500\left(1+\frac{0.08}{1}\right)^{1\cdot  2}\implies 3500(1.08^2)
6 0
3 years ago
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