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4 years ago

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n) = -16 + (n - 1) (1/5)

Mathematics

1 answer:

yKpoI14uk [10]4 years ago

5 0

Answer:

first term is -16

Fourth term is -15.4

Tenth term is -14.2

Step-by-step explanation:

Replace 'n' by the number of the term you want to find and simplify the equation.

Example to find the fourth term

A4= -16 + (4-1)(1/5)

A4 = -16 + 3/5

A4= (-80 + 3)/5

A4= -15.4

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Answer:what does the graph look like

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3 years ago

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UseU={1,2,3,4,5,6,7,8,9,10},A={1,3,4},B={4,7,8,9},and C={2,6,10}to find the given set AUB

salantis [7]

Answer:

A ∪ B = { 1,3,4,7,8,9}

Step-by-step explanation:

U = {1,2,3,4,5,6,7,8,9,10}

A={1,3,4} B={4,7,8,9} and C={2,6,10}

UNION OF SETS:

Union of two sets is defined as the set which has all the elements from both the sets.

Also, REPETITION OF THE ELEMENTS in NOT allowed in union of sets.

Now, here:

A={1,3,4} B={4,7,8,9}

So, A ∪ B = { 1,3,4,7,8,9} ( element 4 is written only ONCE here)

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3 years ago

What is the solution to this equation?<br> 3x-3 = 15

ICE Princess25 [194]

Answer:

Step-by-step explanation:

3x-3=15

-3 -3

x=6

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3 years ago

Write each expression as a product of linear factors 1. X^2+1/2x 2. X^2+2x-3 3. (2x-3)^2 4. X^3+2x^2-19x-20

Grace [21]

Answer:

1. X^2+1/2x = $x(x+\frac{1}{2})$

2. X^2+2x-3 = $(x-1)(x+3)$

3. (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 = $(x+1)(x-4)(x+5)$

Step-by-step explanation:

Each expression can be written as a product of linear factors as follows

1. X^2+1/2x ⇒ $x^{2} + \frac{1}{2}x$

$x^{2} + \frac{1}{2}x$ = $x(x+\frac{1}{2})$

Hence, X^2+1/2x = $x(x+\frac{1}{2})$

2. X^2+2x-3 ⇒ $x^{2} +2x-3$

$x^{2} +2x-3 = x^{2} +3x-x-3$

$x^{2} +3x-x-3 = x(x+3) -1(x+3)$

$x(x+3) -1(x+3) = (x-1)(x+3)$

Hence, X^2+2x-3 = $(x-1)(x+3)$

3. (2x-3)^2 ⇒ $(2x-3)^{2}$

$(2x-3)^{2} = (2x-3)(2x-3)$

Hence, (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 ⇒ $x^{3}+2x^{2} -19x -20$

$x^{3}+2x^{2} -19x -20 = (x+1)(x^{2} +x-20)$

First,

$x^{2} +x-20 = x^{2} +5x-4x-20\\x^{2} +5x-4x-20= x(x+5)-4(x+5)\\x(x+5)-4(x+5) = (x-4)(x+5)$

∴ $(x+1)(x^{2} +x-20) = (x+1)(x-4)(x+5)$

Hence, X^3+2x^2-19x-20 = $(x+1)(x-4)(x+5)$

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3 years ago

Convert the improper fraction 15/12 into a mixed number<br> 31/12

kati45 [8]

Answer:

Divide 15 by 12. The remainder, 3, will be 3/12, or 1/4. Add 1 and 1/4, and you'll get 1 1/4.

Step-by-step explanation:

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3 years ago

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