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Jobisdone [24]
3 years ago
9

10. Which is the graph of the exponential function y = 9(3)x?

Mathematics
1 answer:
NemiM [27]3 years ago
4 0

Answer:

The answer is B

Step-by-step explanation:

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Given the graph of the function f(x) below what happens to f(x) when x is a very small positive number?
vladimir2022 [97]

Answer:  The correct option is

(B) f(x) is a very large positive number.

Step-by-step explanation:  We are given the graph of a function f(x) as shown in the figure.

We are to check what happens to the f(x) when x is a small positive integer.

From the graph, we see that

when x is approaching to 0 from left hand side, then the value of f(x) is approaching to negative infinity.

And,

when x is approaching to 0 from right hand side, then the value of f(x) is approaching to positive infinity.

So, when x is a very smell positive integer, then y is approaching to positive infinity.

That is, the value of f(x) is a very large positive number.

Option (B) is CORRECT.

4 0
3 years ago
6. Pamel bought an electric drill at 85% of the regular price. She paid $276,25 for
Katen [24]

Answer:

£325

Step-by-step explanation:

She paid £276.25 which is 85%

Divide 276.25 by 85 which is 3.25

3.25 is 1%

Multiply 3.25 by 100 to get the full Price

3.25 x 100 = £325

3 0
3 years ago
Is this a very large pr very small number 10^56
lozanna [386]
10 to the 56th power is huge. Imagine multiplying 10 56 times.
8 0
4 years ago
Read 2 more answers
Suppose ABCD is a convex quadrilateral. Points M and N are midpoints of sides BC and AD, respectively. The area of the quadrilat
Katena32 [7]

Answer:

12 unit²

Step-by-step explanation:

area ΔAMC = 1/2 CM x AH' = 1/4 BC x AH'

area ΔABM = 1/2 BM x AH' = 1/4 BC x AH'

area ΔAMC = area ΔABM

for the same calculation, we can prove

area ΔACN = area ΔDCN

area ΔAMC + area ΔACN = 6

area ΔABM + area ΔDCN = 6

ABCD = area ΔAMC + area ΔACN + area ΔABM + area ΔDCN = 6 = 6 = 12

7 0
3 years ago
What is the difference between -4 and 6
LenaWriter [7]

Hey,

Answer:

2 and -2

Good luck :)

4 0
3 years ago
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