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oksano4ka [1.4K]
3 years ago
6

What is the image of (9,3) after a dilation by a scale factor of 3 centered at the origin?

Mathematics
1 answer:
sergiy2304 [10]3 years ago
7 0

Answer:  (27, 9)

Multiply the original coordinates by the scale factor 3 to get this answer

9*3 = 27

3*3 = 9

This only works if the center of dilation is the origin.

The general rule is (x,y) \to (kx, ky) where k is the scale factor.

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If y = 3x^3 - 2x and dx/dt equals 3, find dy/dt when x = -2. Give only the numerical answer. For example, if dy, dt = 4, type on
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Answer:

 \frac{dy}{dt}  = 102

Step-by-step explanation:

<u>step(i)</u>

Given function y = 3 x³ - 2 x  ... (i)

Differentiating equation (i) with respective to 'x'

    \frac{dy}{dx} = 3 (3 x^{2} ) - 2(1)

Given x = -2

(\frac{dy}{dx} ) x_{=-2} = 3 (3 (-2)^{2} ) - 2(1)

(\frac{dy}{dx} ) x_{=-2} = 36 -2 =34

<u><em>Step(ii):-</em></u>

<u><em>we know that </em></u>

                     \frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

Given    \frac{dx}{dt} = 3  and \frac{dy}{dx} = 34

                  \frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

substitute values    \frac{dx}{dt} = 3  and \frac{dy}{dx} = 34  

           ⇒        34 = \frac{\frac{dy}{dt} }{3 }

cross multiplication , we get

                      \frac{dy}{dt} = 34( 3 ) = 102

<u><em>Final answer</em></u>:-

 \frac{dy}{dt} = 34( 3 ) = 102

8 0
3 years ago
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