Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130

The width would be x-4 and
Length would be x
Add all of the sides together
(x-4)+(x-4) + x + x =72,
Which would come out
4x-8=72
Subtract 8 fro, 72 and you get 64
Then divided 64 by 4
So. Width is 16 and length is 20 . given (x-4)
Answer:
4
<h3>When u have a bank account and are 8 dollars below proficiency and you add 12 dollars to your bank account</h3>
Step-by-step explanation:
add 12 to -8
4
You’ll have to use pythagoras theorem for this question
Answer:
3/5
Step-by-step explanation:
So basically "in" is dividing so you have to divide
1/2 / 5/6 = 3/5