Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
Answer:
x=-20
Step-by-step explanation:
x+9=-11
Subtract 9 from both sides. (-11-9=-20)
x=-20
Answer:
7/13
Step-by-step explanation:
P(A or B) = P(A) + P(B) − P(A and B)
P(red or jack) = P(red) + P(jack) − P(red and jack)
P(red or jack) = 26/52 + 4/52 − 2/52
P(red or jack) = 28/52
P(red or jack) = 7/13
Answer:
See attachment for graph
Step-by-step explanation:
Given
Required
The graph that shows the number of miles in x hours
We have:
Multiply both sides by x
So, the function is:
Answer:
47
Step-by-step explanation:
180 - 133 = 47
