Answer: 3.751*10^18kg
Step-by-step explanation:
δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.
Calculating the density of air at 5km above earth surface
P = 5000m + 6370000m = 6.375*10^6m
δ = 619.09 -(.000097* 6.375*10^6)
δ = 0.715kg/m^3 = density
Since Mass = density*volume...equ2
To calculate volume of air around the spherical earth at height 5km
V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6
Substituting R and r in equation 2 to solve for volume of air
V = 1.085*10^21 - 1.08*10^21
V = 5.25*10^18m^3
Substituting δ and V into equation 2 to solve for mass of air
M = 0.715 * (5.25*10^18)
M = 3.751*10^18kg
Let the two numbers be x and y.
We have x+y=45
⇒ y= 45-x.
The two numbers multiply and get 121, so we have another equation:
x*y = 121 (1)
Plug y= 45-x in (1), we have:
x* (45-x)=121
⇒ 45x - x^2 = 121 (distributive property)
⇒ x^2 - 45x = -121 (multiply -1 on both sides)
⇒ x^2- 45x + 121= 0
⇒ x= 42.128 or x= 2.872
y= 45- 42.128= 2.872
or y= 45- 2.872= 42.128.
Because it does not matter what number, x or y, is larger, the two numbers are 2.872 and 42.128.
Hope this helps~
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Answer:
8. no, no, yes, yes
9. see attached
Step-by-step explanation:
8. Slope-intercept form is ...
y = mx + b . . . . . . . where m is the slope, and b is the y-intercept
You will notice that y is by itself on the left side of the equation, and that there are two terms: an x-term and a constant.
The first two equations are NOT in slope-intercept form.
The last two equations ARE in slope-intercept form.
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9. The values of 3x-1 and y are the same. They are shown in the attached table.
The corresponding (x, y) pairs are (-2, -7), (-1, -4), (0, -1), (1, 2), (2, 5). In each pair, the x-value (first number) comes from the x-column of the table. The y-value (second number) comes from the f(x)- or y-column of the table.
