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2 years ago

What is the slope of a line perpendicular to the line whose equation is x+ 3y = -15 Fully simplify your answer.

Mathematics

1 answer:

alukav5142 [94]2 years ago

3 0

Answer:

Step-by-step explanation:

We can find the slope of the given line in this two way:

1) the faster is calculate -a/b where a is the number the multiply x and b is the number the multiply y. In this case we have -1/3

2) the second method is rewrite the equation in slope intercept form and find the therm that multiply x

3y = -x-15

y = -1/3x - 5

Also in this case we have -1/3

Two perpendicular lines have the the product of the their slope that is -1

So the slope that we are finding is 3

In fact = 3 x -1/3 = -1

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Pls help math problem pls

Dovator [93]

Answer: The fourth choice

Step-by-step explanation:

(f - g)(x) = f(x) - g(x) = 4 $x^{2}$ - 5x - (3 $x^{2}$ + 6x - 4) = $x^{2}$ - 11x + 4

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2 years ago

there are 266 students watching a play in the auditorium. there 10 rows with 20 students in each row and 5 rows with 8 students

kondor19780726 [428]

Let x = number of students in each of the remaining rows

266 = (10 x 20) + (5 x 8) + 2x
266 - (10 x 20) - (5 x 8) = 2x
266 - 200 - 40 = 2x
26 = 2x
x = 26/2
x = 13

8 0

2 years ago

Read 2 more answers

What is the scale factor of ABC to ADEF?

kolbaska11 [484]

Sorry, I haven't learned this yet ;-;

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2 years ago

Polygon CCC has an area of 404040 square units. K 2ennan drew a scaled version of Polygon CCC using a scale factor of \dfrac12 1

nikdorinn [45]

Answer:

Area of polygon D = 10 square units

Step-by-step explanation:

Given:

Polygon C has an area of 40 square units.

It is scaled with a scale factor of $\frac{1}2$ to form a new polygon D.

To find:

The area of polygon D = ?

Solution:

When any polygon is scaled to half, then all the sides of new polygon are half of the original polygon.

And the area becomes one-fourth of the original polygon.

Let us consider this by taking examples:

First of all, let us consider a right angled triangle with sides 6, 8 and 10 units.

Area of a right angled triangle is given by:

$A = \dfrac{1}{2} \times Base \times Height\\\Rightarrow A = \dfrac{1}{2} \times 6 \times 8 = 24\ sq\ units$

If scaled with a factor $\frac{1}{2}$ , the sides will be 3, 4 and 5.

New area, A':

$A' =\dfrac{1}{2} \times 3 \times 4 = 6\ sq\ units = \dfrac{1}4\times A$

i.e. Area becomes one fourth.

Let us consider a rectangle now.

Sides be 8 and 10 units.

Area of a rectangle, A = $Length \times Width$ = 8 $\times$ 10 = 80 sq units.

Now after scaling, the sides will be 4 and 5 units.

New Area, A' = 4 $\times$ 5 =20 sq units

So, $\bold{A' = \frac{1}4 \times A}$

Now, we can apply the same in the given question.

$\therefore$ Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ Area of polygon C

Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ 40 = 10 sq units

4 0

2 years ago

Graph y > x^2 - 5. Click on the graph until the correct one appears.

kenny6666 [7]

$y=x^2\\\\for\ x=\pm2\to y=(\pm2)^2=4\to(-2;\ 4);\ (2;\ 4)\\\\for\ x=\pm1\to y=(\pm1)^2=1\to (-1;\ 1);\ (1;\ 1)\\\\for\ x=0\to y=0^2=0\to (0;\ 0)$

Shift the graph of the function y = x², 5 units down /look at the picture #1/.

$y > x^2-5$ /look at the picture #2/ - your answer

7 0

3 years ago

Read 2 more answers