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jek_recluse [69]
3 years ago
14

What is the greatest common factor (GCF) of 72 and 81? A. 12 B. 3 C. 9 D. 6

Mathematics
2 answers:
lesantik [10]3 years ago
4 0

Answer:

c)9 i think

<h2><em>hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h2><h2 /><h2><em>please</em><em> </em><em>mark</em><em> </em><em>Brainliest</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h2>
allochka39001 [22]3 years ago
4 0
The answer is c which is 9
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Joe has a 28 foot long board. He needs to cut it into 24 equal length part. H owmany feet long should each section of the board
34kurt
28/24 = 1.1(6)ft



Each section of the word should be 1.1(6)feet.

8 0
3 years ago
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Giving brainlest and 20 points
Natali5045456 [20]

Answer:

C. 40 square inches but i could be wrong

4 0
3 years ago
The product of three and a number decreased by ten is thirteen
monitta

Answer:

3x - 10 = 13 would be the verbal expression where x = a number

Hope this helps!

5 0
3 years ago
Callie bought 2 gallons of juice for $2.58 per gallon. She sold the juice in 1 cup servings for 75 cents each. Each servings is
Kryger [21]
Yes she got her money back. To be exact she made a profit of $6.84!

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6 0
3 years ago
Determine the probability of selecting a two-child family with one boy and one girl assuming boys and girls are equally likely
Fittoniya [83]

Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.

For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • Two children, hence n = 2.
  • Equally as likely to be a boy or a girl, hence p = 0.5.

The probability of one of each is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.5)^{1}.(0.5)^{1} = 0.5

0.5 = 50% probability of selecting a two-child family with one boy and one girl.

A similar problem is given at brainly.com/question/24863377

3 0
3 years ago
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