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WARRIOR [948]
3 years ago
6

6. Identify the process of adding a value at the end of the sequence to ensure an input sequence by

Computers and Technology
1 answer:
natali 33 [55]3 years ago
4 0

Answer:

Validity check

Explanation:

We add something like CRC, Checksum, parity bit at the end of a sequence for ensuring the input sequence is correct. And an examination with the help of CRC,  Checksum or the parity bit is done by the receiver at the receiver end. And this is the validity check. And the code added is of two types, error detection code, and error detection and correction code.

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Swapping two numbers
Tju [1.3M]

Answer:

Swapping two numbers means exchange the values of two variables with each other.

8 0
3 years ago
Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

           print("Scalene Triangle")

   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

4 0
2 years ago
What will be the results from running the following code?
kari74 [83]

Answer:syntax error

Explanation:

Correct on edg 2021

4 0
2 years ago
Write a program that calculates the occupancy rate for ahotel. The program should start by asking the user how many floorsthe ho
Oksana_A [137]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

using namespace std;   //to identify objects like cin cout

int main(){  //start of main function

       int MinFloors = 1;  //minimum number of floors

       int MinRooms  = 10; //minimum number of rooms

       int NoOfFloors;  //stores number of floors

       int NoOfRooms;  //stores number of rooms

       int OccupiedRooms;  //stores number of rooms occupied

       double TotalRooms=0, TotalOccupied=0;   //stores computed total number of rooms and total number of occupied rooms

       cout<<"How many floors does the hotel have? ";  //prompts user to enter number of floors

       do{  //iterates until the user enters valid number of floors

           cout<<"(cannot be less than "<<MinFloors<<"): ";  //error message

           cin >>NoOfFloors;  //reads number of floors from user

       }while(NoOfFloors<MinFloors);  //repeats as long as number of floors is less than minimum number of floors

       for(int floor=1; floor <= NoOfFloors; floor++){    //iterates through the floors to skip third iteration

           if(floor == 3){   //if floor is third floor

               continue;             }  

           cout<<"How many rooms are on floor " <<floor;  //prompts user to enter number of floors

           do{  //start of do while loop

               cout<<"(cannot be less than "<<MinRooms<<"): ";  //error message

               cin >>NoOfRooms;  //reads number of rooms from user

           }while(NoOfRooms<MinRooms);    //iterates as long as number of rooms are less than valid minimum number of rooms

           TotalRooms += NoOfRooms;   //adds number of rooms to the count of total number of rooms

           cout<<"How many of those rooms are occupied?";  //prompts user to enter number of rooms occupied

           do{  //start of do while loop

         cout<<"(cannot be less than 0 or greater than "<<NoOfRooms<<"): ";  //generates error message

         cin >>OccupiedRooms;  //reads number of rooms occupied by user

           }while(OccupiedRooms<0 || OccupiedRooms>NoOfRooms);   //iterates as long as the number of occupied rooms are less than 0 or greater than number of rooms

           TotalOccupied += OccupiedRooms;    }    //adds number of rooms occupied to the count of total number of occupied rooms    

       cout<<"\nThe hotel has a total of "<<TotalRooms<<" rooms"<<endl;  //displays the total number of rooms in the hotel

       cout<<TotalOccupied<<" are occupied."<<endl;  //displays the total number of occupied rooms

       cout<<(TotalRooms-TotalOccupied)<<" are unoccupied."<<endl;  //displays the total number of unoccupied rooms

cout<<"The occupancy rate is: "<<100*(TotalOccupied/TotalRooms)<<"%"<<endl;     }  //computes and displays the occupancy rate

   

Explanation:

The program first prompts the user to enter number of floors in the hotel. Lets say user enters 6. This is stored in NoOfFloors So

NoOfFloors = 6

So the loop runs for 6 times

Next it asks user to enter the number of rooms in the floor 1. Lets say user enters 12 so this is stored in NoOfRooms so

NoOfRooms = 12

TotalRooms += NoOfRooms;

this statement keeps adding number of rooms to TotalRooms so

TotalRooms = 12

Next program asks user about the number of occupied rooms. Lets say user enters 10 so this is stored in OccupiedRooms so

OccupiedRooms = 10

this statement keeps adding number of rooms to TotalOccupied so

 TotalOccupied += OccupiedRooms;

TotalOccupied = 10

At next iteration program asks user again to enter number of rooms in floor 2. Suppose user enters 14 so

NoOfRooms = 12

TotalRooms += NoOfRooms;

TotalRooms = 12+14

TotalRooms = 26

Program asks again to enter number of occupied rooms so it becomes:

OccupiedRooms = 8

this statement keeps adding number of rooms to TotalOccupied so

 TotalOccupied += OccupiedRooms;

TotalOccupied = 10+8

TotalOccupied = 18

Next is skips floor 3 and iteration 3. and asks user to enter number of rooms in floor 4. Suppose user enters 14

Number of rooms become:

TotalRooms = 12+14+14

TotalRooms = 40

and suppose user enters 14 as occupied rooms so total occupied become:

TotalOccupied = 10+8 + 14

TotalOccupied = 32

For floor 5: Suppose user enters 13

TotalRooms = 12+14+14+13

TotalRooms = 53

For floor 5: Suppose user enters 10

TotalOccupied = 10+8 + 14+10

TotalOccupied = 42

For floor 6: Suppose user enters 12

TotalRooms = 12+14+14+13+12

TotalRooms = 65

For floor 6: Suppose user enters 11

TotalOccupied = 10+8 + 14+10+11

TotalOccupied = 53

Now the loop breaks

Hence

TotalRooms = 65

TotalOccupied  = 53

total unoccupied = TotalRooms-TotalOccupied = 65-53 = 12

The occupancy rate is: 100*(TotalOccupied/TotalRooms) = 100*(53/65) = 81.5385

The output of the program is attached in a screenshot.

6 0
3 years ago
What will be displayed after the following code executes? (Note: the order of the display of entries in a dictionary are not in
iren [92.7K]

Answer:

Nothing will be printed

Explanation:

You can easily find out that FL is not a member of the Dictionary. And we are checking these in the if. Since the if condition ends up being false, the further process will not run as they will only if the condition ends up being true. Hence, nothing will be printed.

Remember, del is used to delete a dictionary item. If this would have been a true condition for if then the FL item in the dictionary would have been deleted as it, in that case, would have been present there. And then the next line would have again added the FL item, and print would have printed the dictionary items with FL item as well. However, since if the condition is ending up being false, nothing will be printed.

If cities['FL'] and print is outside if then

the output will be

{'FL': 'Tallahassee', 'GA': 'Atlanta', 'NY': 'Albany', 'CA': 'San Diego'}

6 0
3 years ago
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