Question

Assume that two marbles are drawn without replacement from a box with 1 blue, 3 white, 2 green, and 2 red marbles. Find the probability of the indicated result. 16) The second marble is blue, given that the first marble is white

Answer 1

Answer:

second marble is blue and  first marble is white is  $\frac{1}{7}$

Step-by-step explanation:

given data

two marbles

box = 1 blue, 3 white, 2 green, and 2 red marbles

                                                                           

solution

we get here second marble is blue and given that the first marble is white

= P(3c1 × 1c1) ÷ P(3c1 × 7c1)          ................................................1

= 1c1 ÷ 7c1

= 1 ÷ 7

so second marble is blue and  first marble is white is  $\frac{1}{7}$