The question requires to balance the equation.
The equation is already balanced, so the answer is:
<span>Ca(s)+Br2(l)⟶CaBr2(s)
</span><span>
</span><span>
</span><span>Explanation:
</span><span>
</span><span>
</span><span>1) The phases are identified with a letter to the right of the compound or element:
</span><span>
</span><span>
</span><span>So, for Ca, the phase is (s) which means solid.
</span><span>
</span><span>
</span><span>For Br₂ (l) the phase is (l) which means liquid.
</span><span>
</span><span>
</span><span>For CaBr₂(s) the phase is (s) which means solid.
</span><span>
</span><span>
</span><span>2) The core work of balancing is make the number of atoms of each element on the reactants equal to the same number of atoms on the products side.
</span><span>
</span><span>
</span><span>That is the law of conservation of mass applied to chemcial reactions.
</span><span>
</span><span>
</span><span>3) So, you have to add coefficientes on the right place to make the number of atoms on the left side equal to the number of the same kind of atom on the right side.
</span><span>
</span><span>
</span><span>In this table you can verify that the equation given is balanced:
</span><span>
</span><span>
</span><span>atom left side right side
</span><span>
</span><span>Ca 1 1
</span><span>
</span><span>Br 2 2
</span><span>
</span><span>So, you do not need to modify any coefficients.
</span>
Answer:
the temperature and pressure at which the three phases of that substance coexist in thermodynamic equilibrium
Explanation:
thats just the answer i have no more to say
Answer:
Solution given:
1 mole of KCl
22.4l
1 mole of KCl74.55g
we have
0.14 mole of KCl74.55*0.14=10.347g
74.55g of KCl22.4l
10.347 g of KCl22.4/74.55*10.347=3.11litre
volume of each solution contains 0.14 mol of KCl contain 3.11litre.
