Ca(s)+br2(l)⟶cabr2(s) express your answer as a chemical equation. identify all of the phases in your answer.

1 answer:

3 0

The question requires to balance the equation.

The equation is already balanced, so the answer is:

Ca(s)+Br2(l)⟶CaBr2(s)


Explanation:


1) The phases are identified with a letter to the right of the compound or element:


So, for Ca, the phase is (s) which means solid.


For Br₂ (l) the phase is (l) which means liquid.


For CaBr₂(s) the phase is (s) which means solid.


2) The core work of balancing is make the number of atoms of each element on the reactants equal to the same number of atoms on the products side.


That is the law of conservation of mass applied to chemcial reactions.


3) So, you have to add coefficientes on the right place to make the number of atoms on the left side equal to the number of the same kind of atom on the right side.


In this table you can verify that the equation given is balanced:


atom left side right side

Ca 1 1

Br 2 2

So, you do not need to modify any coefficients.

You might be interested in

If 1,000 mL = 1 L, which of the following are possible conversion factors for liters and milliliters? Check all that apply.

Fudgin [204]

Answer:

Two conversion factors:

$1=\dfrac{1L}{1,000ml}\\ \\ \\ 1=\dfrac{1,000mL}{1L}$

Explanation:

You can create two possible conversion factors, one to convert from mL to L, and one to convert from L to mL

a) From mL to L

To convert mL to L you need to multiply by a conversion factor that has mL on the denominator and L in the numerator.

Your starting point is: $1,000mL=1L$

Then, divide both sides by 1,000mL (this will be on the denominator of the fraction);

$1,000mL=1L\\\\ \\\dfrac{1,000ml}{1,000mL}=\dfrac{1L}{1,000mL}\\ \\ \\ 1=\dfrac{1L}{1,000mL}$

b) From L to mL

Divide both sides by 1 L:

$1,000mL=1L\\\\ \\\dfrac{1,000ml}{1L}=\dfrac{1L}{1L}\\ \\ \\ 1=\dfrac{1,000mL}{1L}$

7 0

3 years ago

Read 2 more answers

Justin B. Believes that the temperature lowering during the fall months is what causes the color of the leaves to change. He set

Taya2010 [7]

Answer:

This question is incomplete, the remaining part of the question is:

What is the control group, independent variable and dependent variable?

Control group: Plants placed in 80 degree rooms

Independent variable: Change in temperature

Dependent variable: Change in color of leaves

Explanation:

The independent variable in a scientific experiment is the variable that the experimenter controls or manipulates in order to bring about a change in the dependent variable. In this experiment, the variable manipulated by Justin B is the TEMPERATURE CHANGE.

On the other hand, a variable is said to be dependent if it is the variable that responds to a change made to the independent variable or rather it is the outcome. In this experiment, Justin B is trying to see the outcome on the color change in leaves when exposed to a low temperature, hence, COLOR CHANGE IN LEAVES is the dependent variable.

Control group of an experiment is the group that receives no experimental treatment. It is the group the experimenter considers normal and hence is comparing with his experimental group. In this experiment, Justin B believes the leaves change color in a low temperature, hence, he placed some plants in a lower temperature (60 degree) in order to compare them with when the plants are placed in a higher temperature (80 degree). As far as this experiment is concerned, the plants placed in 80 degrees temperature are believed by Justin B not to undergo color change, hence, they are the CONTROL GROUP while the group he placed in 60 degrees temperature are what he is interested in, making them the EXPERIMENTAL GROUP

5 0

3 years ago

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔

Vilka [71]

Answer : The correct option is, (C) 1.1

Solution : Given,

Initial moles of $N_2O_4$ = 1.0 mole