Explanation:
Electromagnetic wave Wavelength
(1) Microwave = 1 m to 1 mm =
to 
(2) Ultraviolet = 10 nm to 400 nm
(3) Radio waves = 1 mm to 100 km =
to 
(4) Infrared = 700 nm to 1 mm
(5) X-ray = 0.01 nm to 10 nm
(6) Visible = 400 nm t0 700 nm
a) In order of increasing wavelength:
: 5 < 2 < 6 < 4 < 1 < 3
b) Frequency of the electromagnetic wave given as:

= frequency
= Wavelength
c = speed of light

So, the increasing order of frequency:
: 3 < 1 < 4 < 6 < 2 < 5
c) Energy(E) of the electromagnetic wave is given by Planck's equation :


So, the increasing order of energy:
: 3 < 1 < 4 < 6 < 2 < 5
Answer: Attractive forces between particels
Explanation:
Answer:
5,250g
Explanation:
Density = Mass / Volume
*Note: mass = x
1.50g/mL = x / 3500mL
multiply 3500mL on both sides
1.50g/mL * 3500mL = 3500mL(x) / 3500mL
cancel units
x = 5250g
Answer:
1: At temperatures below 542.55 K
2: At temperatures above 660 K
Explanation:
Hello there!
In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:

Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:
1:

It means that at temperatures lower than 542.55 K the reaction will be spontaneous.
2:

It means that at temperatures higher than 660 K the reaction will be spontaneous.
Best regards!
Answer:

Explanation:
First, we find in the tables the ΔH of formation of each compound. As you can see in the (image 1)
Then we solve the ecuation for ΔH°reaction
ΔH°reaction=∑ΔH°f(products)−∑ΔH°f(Reactants)
ΔH°reaction= (-2* 393.5 - 2*285.8) - (52.4 + 0) kJ/mol
ΔH°reaction = -1.41 *10^3 kJ/mol