0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.
Explanation:
Data given:
Volume of the base = 47 ml
molarity of the base= 0.39 M
volume of the acid = 25 ml
molarity of the acid =?
For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined. The formula used:
Macid X Vacid = Vbase x Mbase
Macid = 
putting the values given in the rearranged equation above:
Macid = 
= 0.73 M
The concentration of the sulphuric acid needed is 0.73 M.
Answer:
- 10.555 kJ/mol.
Explanation:
∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.
Where, ∆G°rxn is the standard free energy change of the reaction (J/mol).
∆H°rxn is the standard enthalpy change of the reaction (J/mol).
T is the temperature of the reaction (K).
∆S°rxn is the standard entorpy change of the reaction (J/mol.K).
∵ ∆H°rxn = ∑∆H°products - ∑∆H°reactants
<em>∴ ∆H°rxn = (2 x ∆H°f NOCl) - (1 x ∆H°f Cl₂) - (2 x ∆H°f NO) </em>= (2 x 51.71 kJ/mol) - (1 x 0) - (2 x 90.29 kJ/mol) = - 77.16 kJ/mol.
∵ ∆S°rxn = ∑∆S°products - ∑∆S°reactants
<em>∴ ∆S°rxn = (2 x ∆S° NOCl) - (1 x ∆S° Cl₂) - (2 x ∆S° NO) </em>= (2 x 261.6 J/mol.K) - (1 x 223.0 J/mol.K) - (2 x 210.65 J/mol.K) =<em> - 121.1 J/mol.K. = - 0.1211 kJ/mol.K.</em>
<em></em>
∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.
<em>∴ ∆G°rxn = ∆H°rxn - T∆S°rxn </em>= (- 77.16 kJ/mol) - (550 K)(- 0.1211 kJ/mol.K) = <em>- 10.555 kJ/mol.</em>
Answer:
V = 56.72 L
Explanation:
Given data:
Number of mole of neon gas = 0.83 mol
Temperature = 35°C
Pressure = 0.37 atm
Volume of gas = ?
Solution;
Temperature = 35°C (35+273 =308K)
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
Now we will put the values in formula.
V = nRT/P
V = 0.83 mol ×0.0821 atm.L/mol.K ×308K / 0.37 atm
V = 20.99 L/ 0.37
V = 56.72 L
What do you think it is? do you know? Do you even pay attention?
Well the answer would be <span>The process is called "lithification"-- the particles of sediment are pressed together (compaction) and held together by minerals left behind when the water is forced out</span>
Para and ortho is actually indicating different name structure of mixture. So if structure is different then boiling/distill/melt temprature will be also different.
