Answer:
67,365,043,200
Step-by-step explanation:
A coin toss has 2 possible outcomes. A coin tossed 3 times has 2³ = 8 possible permutations.
A standard die has 6 possible outcomes. A die rolled 4 times has 6⁴ = 1296 possible permutations.
The number of ways 4 cards can be chosen from a deck of 52 without replacements is 52×51×50×49 = 6,497,400.
The total number of possible outcomes is:
8 × 1296 × 6,497,400 = 67,365,043,200
Answer:
<h2>
4</h2>
Option A is the right option.
solution,
∆ABC~∆EDC
putting the values,
Hope this helps..
Good luck on your assignment..
Answer:
the answer is smallest to biggest
Step-by-step explanation:
Answer:
Step-by-step explanation:
Assuming the decay factor, m = 0.0005
f(x) = 
f(9000) = 
= 1 - 0.0111 = 0.99
