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11Alexandr11 [23.1K]
3 years ago
10

A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rect

angle.
Mathematics
2 answers:
gayaneshka [121]3 years ago
7 0
Hello,

It 's difficult to translate that in french.

l=16 ^(1/5)
w=2^(1/5)
Area=32^(1/5)=(2^5)^(1/5)=2 (in²)


maw [93]3 years ago
5 0

Answer:

1.998\\

Step-by-step explanation:

Given

Width of the rectangle = 2^{\frac{1}{5} } \\

Length of the rectangle = 16^{\frac{1}{5} } \\

The area of rectangle

= Length * width\\

= 2^{\frac{1}{5} } * 16^{\frac{1}{5} } \\= 1.148 * 1.741\\ 1.998\\

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andreyandreev [35.5K]

Answer:

12

Step-by-step explanation:

3+5=8

32÷8=4

3×4=12

7 0
3 years ago
Points E, F, and D are on circle C, and angle G measures 60°. The measure of arc EF equals the measure of arc FD.
galben [10]

Answer:

∠EFD ≅ ∠EGD ⇒ A

Arc ED ≅ arc FD ⇒ C

m arc FD = 120° ⇒ E

Step-by-step explanation:

Let us revise some facts

  1. Equal chords subtended equal arcs
  2. The measure of an inscribed angle is one-half the measure of the central angle which subtended by the same arc
  3. The measure of a central angle is equal to the measure of its subtended arc
  4. If one angle of an isosceles triangle measure 60° then the triangle is equilateral
  5. The sum of the measures of the interior angles of any quadrilateral is 360°

In the quadrilateral  CDGE

∵ m∠G = 60°

∵ m∠GDC = m∠GEC = 90°

- By using the 5th rule above

∴ m∠G + m∠GDC + m∠DCE + m∠GEC = 360°

∴ 60 + 90 + m∠DCE + 90 = 360

∴ 240 + m∠DCE = 360

- Subtract 240 from both sides

∵ m∠DCE = 120°

In circle C

∵ ∠DCE is a central angle subtended by arc DE

∵ ∠DFE is an inscribed angle subtended by arc DE

- By using the 2nd rule above

∴ m∠DFE = \frac{1}{2} m∠∠DCE

∵ m∠DCE = 120°

∴ m∠DFE = \frac{1}{2} (120)

∴ m∠DFE = 60°

- That means ∠EFD ≅ ∠EGD because their measure is 60°

∴ ∠EFD ≅ ∠EGD

In Δ EFD

∵ EF = FD

∵ m∠DFE = 60°

- By using the 4th rule above

∴ Δ EFD is an equilateral triangle

∴ ED = FD = FE

In circle C

∵ Side ED subtended by arc ED

∵ Side FD subtended by FD

∵ Side ED ≅ side FD ⇒ proved

- By using the 1st rule above

∴ Arc ED ≅ arc FD

∵ m∠ECD = 120°

∵ ∠ECD is a central angle subtended by arc ED

- By using the 3rd rule above

∴ m∠ECD = m arc ED

∴ m of arc ED = 120°

∵ Arc ED ≅ arc FD

∴ m arc ED = m arc FD

∴ m arc FD = 120°

5 0
3 years ago
Read 2 more answers
State the domain and range of the following function:
mojhsa [17]

Answer:

Domain = \{-3,0,2,1,6,3\}

Range = \{4,6,-2,-3,-7,2\}

Step-by-step explanation:

Given

\{(- 3,4), (0,6), (2, - 2), (1, - 3), (6, - 7), (3, 2)\}

Required

The domain and range

A function is represented as:

Function = \{(x_1,y_1),(x_2,y_2),....(x_n,y_n)\}

Where

x \to domain

y \to range

So, we have:

Domain = \{-3,0,2,1,6,3\}

Range = \{4,6,-2,-3,-7,2\}

7 0
3 years ago
Find the circumferences of both circles
nika2105 [10]

Answer:

Both circles

Step-by-step explanation:

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Tree times the sum of ten and a number is 25. What is the number? <br><br> (Fraction)
ella [17]

Answer:

Step-by-step explanation:

3(10+n) = 25

30 +3n =25

30-30 and 25-30=

3n=-5

3/3 and 5/-3

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3 years ago
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