Answer:
Green and Blue ribbon
Step-by-step explanation:
Given
They collect
Red Ribbon = ½ mile
Green Ribbon = ⅛ mile
Blue Ribbon = ¼ mile
To find?
Which colors of ribbons will be collected at the ¾ mile mark.
The interpretation of the question is to test which of the above fractions can divide ¾ without a remainder; in other words, multiples of ¾.
Testing each fraction.
Red Ribbon = ½
¾ ÷ ½
= ¾ * 2
= 3/2
= 1.5 or 1 Remainder 1
This is not an exact multiple of ¾. So, the red ribbon won't be passed here.
Green Ribbon = ⅛
¾ ÷ ⅛
= ¾ * 8
= 24/8
= 3
This is an exact multiple of ¾. So, the green ribbon will be collected.
Testing the last ribbon
Blue = ¼
¾ ÷ ¼
= ¾ * 4
= 3
This is an exact multiple of ¾. So, the blue ribbon will be collected.
Hence, the green and blue ribbons will be collected at ¾ mile mark
To determine how many times larger the peach got, you will divide the new diameter by the original diameter length.
188869/98 = 1927.2
The new diameter is approximately 1927 times longer.
To convert this to scientific notation, move the decimal point from the end (on the right) to between the 1 and the 9 to get 1.927.
Then count the number of decimal places you moved to get there, because this represents how many groups of 10 you adjusted your place value by and then becomes your exponent in scientific notation.
1.927 x 10^3 times is the answer in scientific notation.
Answer:
C. x = 3/13
Step-by-step explanation:
Answer:
7/15
Step-by-step explanation:
Well 4/5 - 1/3 = 12 / 15 - 5 / 15 which is equal to 7/15, but there aren't any expressions in your question.
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
