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3 years ago

What is the value of S in the equation 1/3s+14=26

Mathematics

1 answer:

Law Incorporation [45]3 years ago

4 0

First, isolate 1/3s:
1/3s=12
Second, multiply both sides by 3 to get a singular value of s (just s):
s=36

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You're at a clothing store that dyes your clothes while you wait. You get to pick from 444 pieces of clothing (shirt, pants, soc

AlexFokin [52]

Answer:

1/12

Step-by-step explanation:

There are 4 clothing choices and 3 colors.

4x3=12

This means you have a 1 in 12 chance of getting an orange hat.

This presupposes that there are EQUAL numbers of pieces and colors. (111 of each).

4 0

3 years ago

Solve for x.<br><br> x+23=−22<br><br> someone help

BaLLatris [955]

Answer:

x = - 45

Step-by-step explanation:

x+23(-23)=−22 (-23)First subtract 23 from both sides

x = - 45

7 0

3 years ago

In a normal distribution what percent of values fall within one standard deviation of the mean?

Sophie [7]

The answer is given by the empirical rule, 68%.

8 0

3 years ago

Find the annual infiltration rate for the nearest 10th of a percent of a gallon of milk that increases the value from $1.51 to $

Leno4ka [110]

Answer:

7.429 cents

Step-by-step explanation:

Given that:

Price change = $1.51 to $2.03

Period of time = 7 years

Therefore, the annual inflation rate :

Difference in price / number of years

($2.03 - $1.51) / 7

$0.52 / 7

= 0.0742857 per year

= 0.0742857 * 100 (about 7.429 cents per year)

5 0

2 years ago

ITS TIMED PLEASE HELP

Lubov Fominskaja [6]

Answer:

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

$f(x)=\frac{1}{2}x^{2}-4x+5$

Convert to vertex form

$f(x)-5=\frac{1}{2}x^{2}-4x$

Factor the leading coefficient

$f(x)-5=\frac{1}{2}(x^{2}-8x)$

$f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x^{2}-8x+16)$

$f(x)+3=\frac{1}{2}(x-4)^{2}$

$f(x)=\frac{1}{2}(x-4)^{2}-3$

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function $f(x)=\frac{1}{2}x^{2}-4x+5$ has a minimum located at (4,-3)

5 0

3 years ago