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s2008m [1.1K]
2 years ago
7

Solve for x and y: 3/x -1/y =13/10 1/x + 2/y =9/10

Mathematics
1 answer:
harkovskaia [24]2 years ago
3 0

Answer:

  (x, y) = (2, 5)

Step-by-step explanation:

I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...

  3x' -y' = 13/10

  x' +2y' = 9/10

Adding twice the first equation to the second, we get ...

  2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)

  7x' = 35/10 . . . . . . simplify

  x' = 5/10 = 1/2 . . . . divide by 7

Using the first equation to find y', we have ...

  y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5

So, the solution is ...

  x = 1/x' = 1/(1/2) = 2

  y = 1/y' = 1/(1/5) = 5

  (x, y) = (2, 5)

_____

The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.

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5 0
2 years ago
What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b
kramer

Option C: a=3, b=4 is the value of a and b

Explanation:

Given that the expression \sqrt{648}=\sqrt{2^a\times3^b}

We need to determine the value of a and b

Let us consider the term \sqrt{648} and take the prime factorization of the term 648

Thus, we have,

648 divides by 2,

648=2 \cdot 324

324 divides by 2,

648=2 \cdot 2 \cdot 162

162 divides by 2,

648=2 \cdot 2 \cdot 2 \cdot 81

81 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 27

27 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 9

9 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3

Thus, we have,

\sqrt{648}=\sqrt{2^{3} \cdot 3^{4}}

Therefore, equating the powers of 2 and 3, we get,

a=3, b=4

Hence, the value of a and b is 3 and 4

Thus, Option C is the correct answer.

4 0
3 years ago
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PLEASE<br> Need Help<br> Show Work
BartSMP [9]

This set notation really seems the hard way to exclude a single value. Anyway...

The domain doesn't include where the denominator is zero, 4x + 7 = 0,

x = -7/4

The range doesn't include the asymptotic value, which is

y=2x/4x = 1/2

So we need domain x ≠ -7/4 and range y ≠ 1/2

Answer: First choice

7 0
3 years ago
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