Probability that no zebras collide is 0.25
The zebras are represented as z1, z2 and z3.
Z1 to B, Z2 to C, and Z3 to A come first 
Following that, z1 to C, z2 to A, and z3 to B = 
Consequently, the likelihood of no collision is 2×1/8 = 0.25.
<h3>
What are the types of probability distributions ?</h3>
Discrete and continuous probability distributions are the two main categories in which probability distributions fall. There are numerous varieties of probability distributions within each category.
- The number of favorable outcomes of an event divided by the total number of possible outcomes of an event can be used to calculate the probability of an event.
- The likelihood of a sure or certain event is one.
- The likelihood of an impossibility is 0 (0).
- Every event has a probability between 0 and 1.
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mu = 1100 = population mean
sigma = 275 = population standard deviation
x = 1400 = raw score
z = z score
z = (x-mu)/sigma
z = (1400-1100)/(275)
z = 300/275
z = 1.0909090909091 approximately
z = 1.09
Convention is to round to two decimal places so that you can use a Z table to look up the area under the curve (which helps determine probability).
The positive z score is due to Paula's raw score being above the mean.
37 is prime so it is reduced to its lowest form.
33/44 simplifies to 3/4
Hope this helps you out . Of solving for k then just set it equal to zero