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kiruha [24]
3 years ago
9

What is the value of y?

Mathematics
1 answer:
enyata [817]3 years ago
8 0

Answer:

y=68

Step-by-step explanation:

Okay, here we go.

180-56=124

124/2=62

62-12=50

62+50=112

180-112=68

y=68

Have a wonderful day!

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Which inequality is true?
ICE Princess25 [194]

Answer:

∠6 > ∠3 is TRUE.

Step-by-step explanation:

We know that acute angle is less than 90 degree while obtuse angle is more than 90 degree. By looking at the given angles, we can easily determine which angle is obtuse or acute. then we can decide which angle is bigger to find the answer.

∠10 > ∠7

FALSE;

Because∠10 is acute while ∠7 is obtuse.

------------


∠6 > ∠3

TRUE;

Because∠3 is acute while ∠6 is obtuse.

------------

∠9 > ∠11

FALSE;

Because∠9 is acute while ∠11 is obtuse.

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∠8 > ∠11

FALSE;

Because∠8 is acute while ∠11 is obtuse.

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8 0
3 years ago
Freezer A measures 1 ft times 1 ft times 5 ft and sells for ​$300. Freezer B measures 1.5 ft times 1.5 ft times 4 ft and sells f
Sladkaya [172]

Answer:

Freezer A is better option as price per cubic foot is less for Freezer A

Step-by-step explanation:

Data provided in the question:

Measure of Freezer A = 1 ft × 1 ft × 5 ft

Measure of Freezer B = 1.5 ft × 1.5 ft × 4 ft

Price of Freezer  A = $300

Price of Freezer  B = $600

Now,

Volume of Freezer A = 1 ft × 1 ft × 5 ft

= 5 ft³

Volume of Freezer B = 1.5 ft × 1.5 ft × 4 ft

= 9 ft³

Now,

Price per cubic foot for Freezer A = $300 ÷ 5 ft³

= $60/ft³

Price per cubic foot for Freezer B = $600 ÷ 9 ft³

= $66.67/ft³

Hence,

Freezer A is better option as price per cubic foot is less for Freezer A

7 0
3 years ago
Find an equation for the inverse for each of the following.
IgorLugansk [536]

Answer:

  • <em>To solve these first swap x and y, solve for y and name it inverse function</em>

3. <u>y = -8x + 2</u>

  • x = -8y + 2
  • 8y = -x + 2
  • y = -x/8 + 2/8
  • y = -(18)x + 1/4

f⁻¹(x) = -(18)x + 1/4

-----------------------------------------

4.<u> y = (2/3)x - 5</u>

  • x = (2/3)y - 5
  • (2/3)y = x + 5
  • y = (3/2)x + (3/2)5
  • y = 1.5x + 7.5

f⁻¹(x) = 1.5x + 7.5

-----------------------------------------

5. <u>f(x) = 2x² - 6</u>

  • x = 2y² - 6
  • 2y² = x + 6
  • y² = 1/2x + 3
  • y = \sqrt{1/2x + 3}

f⁻¹(x) = \sqrt{1/2x + 3}

-----------------------------------------

6. <u>y = (x - 3)²</u>

  • x = (y - 3)²
  • \sqrt{x} = y - 3
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f⁻¹(x) = 3 +  \sqrt{x}

4 0
3 years ago
Question 2
prisoha [69]

Answer:

Please check the explanation.

Step-by-step explanation:

<u>Calculating the area of the outer rectangle:</u>

Given

  • The length outer rectangle = l = 3x - 1
  • The width of outer rectangle = w = 5x + 2

Thus,

The area of the outer rectangle:

A = wl

    = (5x + 2) (3x - 1)

    =5x\cdot \:3x+5x\left(-1\right)+2\cdot \:3x+2\left(-1\right)

     =5\cdot \:3xx-5\cdot \:1\cdot \:x+2\cdot \:3x-2\cdot \:1

      =15x^2+x-2

<u>Calculating the area of the inner rectangle:</u>

Given

  • The length inner rectangle = l = x + 7
  • The width of inner rectangle = w = x

Thus,

The area of the outer rectangle:

A = wl

   = x(x+7)

   = x² + 7

<u>Calculating the area of the shaded region:</u>

As

The area of the outer rectangle = 15x² + x - 2

The area of the inner rectangle = x² + 7

  • The area of the shaded region can be determined by subtracting the area of the inner rectangle from the area of the outer rectangle.

Thus,

shaded region Area = Outer Rectangle Area - Inner Rectangle Area

                                  = 15x² + x - 2 - (x² + 7)

                                   =  15x² + x - 2 - x² - 7

                                   = 14x² + x - 9

Therefore, the Area of the shaded region is: 14x² + x - 9

4 0
3 years ago
The temperature is -2°C. If the temperature rises by 15°C, what is the new temperature?
Furkat [3]

Answer:

13 C

Step-by-step explanation:

15-2=13

8 0
3 years ago
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