The correct answer is -9/22.
Answer:
Y=4
Step-by-step explanation:
Because the two triangles are congruent you can set the two expressions equal to each other and solve from their.
step 1 ) 8Y = 6Y + 8
step 2 ) isolate the variable to one side 8Y-6Y= 8 => 2Y = 8
step 3 ) solve for Y 2Y/2 = 8/2
Solution Y=4
The answer to the question would be 6
Answer:
The augmented matrix for each set of linear equations is:
a) 
Augmented matrix:
![\left[\begin{array}{ccc}1&-2&0\\3&4&-1\\2&-1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%260%5C%5C3%264%26-1%5C%5C2%26-1%263%5Cend%7Barray%7D%5Cright%5D)
b) 
Augmented matrix:
![\left[\begin{array}{cccc}1&0&1&1\\-1&2&-1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%261%5C%5C-1%262%26-1%263%5Cend%7Barray%7D%5Cright%5D)
c) 
Augmented matrix:
![\left[\begin{array}{cccccc}1&0&1&0&0&1\\0&2&-1&0&1&2\\0&0&2&1&0&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccccc%7D1%260%261%260%260%261%5C%5C0%262%26-1%260%261%262%5C%5C0%260%262%261%260%263%5Cend%7Barray%7D%5Cright%5D)
d) 
Augmented matrix:
![\left[\begin{array}{ccc}1&0&1\\0&1&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%261%5C%5C0%261%262%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
In order to find the augmented matrix, you have to take the numeric values of each variable and make a matrix with them. For example, in the linear system a) you can make a matrix out of the numeric values accompanying x_1 and x_2, this matrix will be:
Then you have to make a vector with the constants in the linear equations, for the case of system a) the vector will be:
To construct the augmented matrix, you append those matrices together and create a new one:
![\left[\begin{array}{ccc}1&-2&0\\3&4&-1\\2&-1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%260%5C%5C3%264%26-1%5C%5C2%26-1%263%5Cend%7Barray%7D%5Cright%5D)