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serg [7]
3 years ago
10

The tram could cover 400 centimeters in 50 seconds. if the rate of the tram were reduced by one half during the thunderstorm<

how far could the tram go in 20000 seconds?
Mathematics
1 answer:
ki77a [65]3 years ago
6 0
Reduced by half = 200cm/50 seconds.

20000/50 = 400.

200 x 400 = 80,000cm
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Write an expression for the calculation the difference of the products of 5 and 2 and 5 and 1
oee [108]
Let's review the terminology.  A product is what you get when you multiply two numbers.  So, the product of 5 and 2 is basically "5*2," and the product of 5 and 1 is "5*1."

The difference means when you subtract one from the other.  So, the difference of 5*2 and 5*1 means "(5*2)-(5*1)".  (Note: I put in parentheses to make sure the reader understands that 5*2 is separate from 5*1.  5*2-5*1 is confusing: you might not know what to do first!)

So, "(5*2)-(5*1)" can be your answer, OR you can simplify it further by actually doing the multiplication: "10-5".  If you want the answer, just subtract--the expression is equal to 5.

Answer: "<span>(5*2)-(5*1)" OR "10-5" OR "5"</span>
3 0
3 years ago
HELP What is the area of a circle with a radius of 13 feet? IT IS NOT 530.93 ft ​
NeTakaya

Answer:

530.66

Step-by-step explanation:

to find the area you need to do pi times the radius square and to find the radius squared you just times it by its self so 13 times 13 which is 169 and pi is 3.14

so now you just do 3.14x169=530.66

8 0
3 years ago
An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

\dfrac{dC}{dw}= 0  \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}

w = \dfrac{88}{3(3)}^{1/3} \ feet

Now;

length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet

height = ( 88})^{1/3} (3)^{1/3} \ feet

6 0
3 years ago
a male elephant weighs 6708 pounds. A female elephant weighs 5823 pounds to the nearest hundred what is the total weight of the
oksian1 [2.3K]
Add the weight of both elephants then round to the nearest 100

5 0
3 years ago
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When three points lie on the same line
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When three points are on the same line it’s collinear,. we’re in the same class LOL
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