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Zielflug [23.3K]
3 years ago
7

Circle O is shown. Line A E is a diameter. Line O C is a radius. A line is drawn from point C to point D on the opposite side of

the circle and intersects diameter A E at point B. Angle D B E is 58 degrees. The measure of arc D E is 50 degrees.
What is the measure of angle AOC?

42°
58°
66°
79°
Mathematics
2 answers:
Montano1993 [528]3 years ago
6 0

Answer:

66

Step-by-step explanation:

maksim [4K]3 years ago
4 0

Answer:

66

Step-by-step explanation:

I did it on edgeniuty

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Alexxx [7]

Consider the function F(x)= x³ +½x² −2x +3. Use calc and algebra to find any and all stationary points on the graph of the function.Precalc need help ASAP

Solution:

the above function has more than one root or more than one solution. The derivative of the function represents the slope of the tangent line to the curve

F(x)= x³ +½x² −2x +3, F'(x) = 3(x3-1)+(1/2)(2)(x2-1)-2(x1-1)+0

F'(x)=3x2+x-2 is the slope of the tangent line

setting the slope =0 and solving the quadratic equations, you find all the

critical points of interest

3x2+x-2=0, solve by factoring (3x-2)(x+1)=0, then 3x-2=0, x= 2/3

and x+1=0, x=-1 substituting these values of x in the original equation

you get the corresponding values of F(x) such that;

F(x)= x³ +½x² −2x +3, F(x)=(2/3)3+1/2(2/3)2-2(2/3)+3

= 8/27+4/18-4/3+3 = 8/27+2/9-4/3+3/1 = 59/27 and the first point is

(2/3, 59/27)

F(x)= x³ +½x² −2x +3, F(x)=(-1)3+1/2(-1)2-2(-1)+3

= -1+1/2+2+3 = 9/2 and the 2nd point is ( -1, 9/2)

these two points represents points where the slope of the tangent line to the curve is 0 and could be either maximum or minimum points

You can also find the y intercepts where x = 0 F(x)= x³ +½x² −2x +3, setting x = 0, y= F(x)=3 and the point ( 0,3) is a y intercept setting y = 0, then x intercepts can be found upon solving the equation x³ +½x² −2x +3 =0

3 0
2 years ago
In a sample of 230 teenagers, 202 would like to have smaller class sizes at their school. Find the sample
marishachu [46]

Answer:

The sample proportion is 0.88.

The margin of error is of 0.04.

The interval likely to contain the true population proportion is (0.84,0.92).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Margin of error:

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Sample of 230 teenagers, 202 would like to have smaller class sizes at their school.

This means that n = 230, and that the sample proportion is:

\pi = \frac{202}{230} = 0.88

The sample proportion is 0.88.

Standard 95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Margin of error:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{0.88*0.12}{230}}

M = 0.04

The margin of error is of 0.04.

Confidence interval:

Sample proportion plus/minus margin of error. So

0.88 - 0.04 = 0.84

0.88 + 0.04 = 0.92

The interval likely to contain the true population proportion is (0.84,0.92).

5 0
3 years ago
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