Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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The area of the cross-section is 169 sq. cm.
That is the correct answer to this problem
Answer:
6
Step-by-step explanation:
Each ice cream cone costs 4 quarters or 10 dimes, so Simon has ...
20/4 + 12/10 = 5 + 1.2 = 6.2
times the price of an ice cream cone. He can buy 6 cones for his friends.
9 students
30% ends up being .3%, multiply .3% by 30 students which equals 9.
The name of the sets of the numbers to which each of the given number belongs is:
- 7 = Natural number. Integer. Rational number.
- √23 = Irrational number.
- л = Irrational number.
- O = Rational number. Integer.
- -0.5 = Rational number.
- -2.5 = Rational number.
- √0.09 = Rational number.
- -√0.9 = Irrational number.
<h3>What are sets of numbers?</h3>
These are the various types of number groups that exist for categorizing numbers.
Natural numbers are all positive numbers from 1 to infinity while integers are positive and negative whole numbers. A decimal cannot be an integer as a result.
Rational numbers are discrete which means that they are terminating and eventually stop going while irrational numbers will keep going to infinity and are therefore non-terminating.
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