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svetoff [14.1K]
3 years ago
11

I need help on this question this is really really hard.

Mathematics
2 answers:
sertanlavr [38]3 years ago
8 0
Yup that persons right take ot from me...i have no clie what was going on so ya its C 4/5
sp2606 [1]3 years ago
7 0
Passed/total=84/105=4/5=C 
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A bag of dog food contains 42 cups of dog food. Your dog eats 2 1/3 cups of dog food each day. How many days does the bag of dog
leva [86]

Answer: you keep adding 2 and 1/3 to get your answer. 18 day so the dog food should last up to 18days hope this helps

Dont take my word not 100% sure

3 0
3 years ago
Solve for X<br> 121 +7&lt; -11<br> OR 5x- 8 &gt; 40
Trava [24]

Answer:

x > 48/5 the first one is false

3 0
2 years ago
Prove or disprove (from i=0 to n) sum([2i]^4) &lt;= (4n)^4. If true use induction, else give the smallest value of n that it doe
ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for n\geq 78

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: \sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4

For n=1: \sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4

From this point we will assume that n\geq 2

As we can see, \sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4 and (4n)^4=256n^4. Then,

\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4

Now, we will use the formula for the sum of the first 4th powers:

\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}

Therefore:

\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0

and, because n \geq 0,

465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1

Observe that, because n \geq 2 and is an integer,

n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5

In concusion, the statement is true if and only if n is a non negative integer such that n\leq 77

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute  (4n)^4- \sum^{n}_{i=0} (2i)^4 for 77 and 78 you will obtain:

(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064

(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992

7 0
3 years ago
A bag is filled with marbles. You take out and mark 80 marbles. Then you put the marbles back in the bag and mix the marbles. In
noname [10]
About 400 marbles. You simply set up a proportion and solve it as I did in the photo attached.

3 0
2 years ago
Read 2 more answers
2. What percent of cal Rs 80 is Rs 20 ? ​
SpyIntel [72]

Answer:

Hope this is helpful to you

7 0
2 years ago
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