3x + 5 = 23
5 more than(addition) 3 times(multiplication) a variable(x) is(equals) 23
(you add 5 to 3x)
If you need to solve for "x", you need to isolate/get the variable "x" by itself in the equation:
3x + 5 = 23 Subtract 5 on both sides
3x + 5 - 5 = 23 - 5
3x = 18 Divide 3 on both sides to get "x" by itself
x = 6
Answer:
its (C) or (B) but my answer would be (B)
Step-by-step explanation:
If you factor it, you can get an equation that is equivalent. So take out a 6. that leaves you with 6(8+3x)
Let the number of girls be x and the number of boys be y
The number of boys is the same as the number of girls.
x = y
The number of boys is twice the number of girls when 8 girls left.
2(x - 8) = y
x = y ---------------- (1)
2(x - 8) = y -------- (2)
Sub (1) into (2)
2(y - 8) = y
2y - 16 = y
2y - y = 16
y = 16
There were 16 boys and 16 girls initially.
16 + 16 = 32
There were a total of 32 students in the class initially.
