What is the slope of the line that passes through (1,-4) and (-4,-6)

Mathematics

1 answer:

Fudgin [204]3 years ago

6 0

The slope of the line is 4/10

remember: rise over run

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Which statement best describes the polynomial 2x+8?

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A
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Which function produces an output of 5 for an input of -6?

kodGreya [7K]

Answer:

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Step-by-step explanation:

Since the input is -6, you input it into the equation. That would make it f(-6)=-(-6)-1 which would be equivalent to f(-6)=6-1 , as the negatives at the beginning of the equation cancel each other out and make it positive. Then you solve and get 5, which is your output. Hope I could help :)

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3 years ago

Read 2 more answers

A ball is thrown from an initial height of 3 meters with an initial upward velocity of 30 m/s. The ball's height h (in meters) a

yanalaym [24]

$h=3+30t-5t^2\implies 13=3+30t-5t^2\implies 0=-10+30t-5t^2 \\\\\\ 5t^2-30t+10=0\implies 5(t^2-6t+2)=0\implies t^2-6t+2=0$

now, it doesn't give us nice looking integers, so let's plug that into the quadratic formula.

$~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{1}t^2\stackrel{\stackrel{b}{\downarrow }}{-6}t\stackrel{\stackrel{c}{\downarrow }}{+2}=0 ~\hspace{10em} t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ t= \cfrac{ - (-6) \pm \sqrt { (-6)^2 -4(1)(2)}}{2(1)}\implies t=\cfrac{6\pm\sqrt{36-8}}{2}$

$t=\cfrac{6\pm\sqrt{28}}{2}\implies t=\cfrac{6\pm\sqrt{2^2\cdot 7}}{2}\implies t=\cfrac{6\pm 2\sqrt{7}}{2}\implies t=\cfrac{2(3\pm 1\sqrt{7})}{2} \\\\\\ t=3\pm \sqrt{7}\implies t= \begin{cases} 3+\sqrt{7}\\ 3-\sqrt{7} \end{cases}\implies t\approx \begin{cases} 5.65\\ 0.35 \end{cases}$

8 0

3 years ago

What is the slope of the line that passes through (1,-4) and (-4,-6)​

What is the slope of the line that passes through (1,-4) and (-4,-6)