Answer:



Step-by-step explanation:
Given
Let the three sides be represented with A, B, C
Let the angles be represented with 
[See Attachment for Triangle]



What the question is to calculate the third length (Side B) and the other 2 angles (
)
Solving for Side B;
When two angles of a triangle are known, the third side is calculated as thus;

Substitute:
,
; 




Take Square root of both sides



<em>(Approximated)</em>
Calculating Angle 

Substitute:
,
; 




Subtract 180 from both sides


Divide both sides by -144



Take arccos of both sides



<em>(Approximated)</em>
Calculating 
Sum of angles in a triangle = 180
Hence;



Make
the subject of formula


360 brainliest? Have a nice day
Answer:
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Step-by-step explanation:
Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.
Let five years ago be group I X and as of now be group II Y

(Two tailed test at 5% level of significance)
Group I Group II combined p
n 270 300 570
favor 120 140 260
p 0.4444 0.4667 0.4561
Std error for differene = 
p difference = -0.0223
Z statistic = p diff/std error = -1.066
p value =0.2864
Since p value >0.05, we accept null hypothesis.
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Answer: 
Step-by-step explanation:
1. By definition, an even number is that number that can be divided by two.
2. Therefore, keeping this definition on mind, if you have an even number
, the next consecutive even integer after it can be obtained by adding 2.
3. Then, you can conclude the expression that represents the first consecutive even integer after
is:

Answer: the third angle is 106 degrees.
The base angles are 37 degrees each.
Step-by-step explanation:
In an isosceles triangle, the base angles are equal.
Let x represent the measure of each of the base angles.
The third angle in an isosceles triangle is 32 more than 2 times as large as each of the two base angles. It means that the measure of the third angle would be
(2x + 32) degrees
The sum of the angles inna triangle is 180 degrees. It means that
x + x + 2x + 32 = 180
4x = 180 - 32
4x = 148
x = 37
The third angle is
2x = 32 = (2 × 37) + 32
= 74 + 32 = 106