Slope-intercept form of a line:
y=mx+b
m=slope
other perpendicular line to this line (y=mx+b) will have the next slope:
m´=-1/m
We have this line in slope-intercet form:
y=1/3x-7
m=1/3
A perpendicular line will have the next slope:
m´=-1/m=-1(1/3)=-3
Now, we have a point (5,-2) and the slope (-3).
point-slope form: given a point (x₀,y₀) and the slope m, the point-slope form will be:
y-y₀=m(x-x₀)
In this case:
y-(-2)=-3(x-5)
y+2=-3x+15
y=-3x+15-2
y=-3x+13
Answer: The equation of a line (slope intercept form) that is perpendicular to the line y=1/3x-7 and passes throught the point (5,-2) is:
y=-3x+13
X = -675
I hope this helps! :)
Solve for x, distibutive 0.2:0.2x - 540
Subtract 0.2x to each side: -540 = x - 0.2x
Combine x: -540 = 0.8x
Divide 0.8 to each side: x = -540/0.8 = -675
Divide 3 by 2 and you should get 1.5
3x-4= 6x-19 » -4+19 = 6x-3x » 15 = 3x » 15/3 = x » x = 5