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3 years ago

Please help!! Is it possible to prove that the triangles are congruent by using the AAS Congruence Theorem?

Mathematics

1 answer:

goldenfox [79]3 years ago

6 0

Answer:

no, there is not enough information to use AAS congruence theorem to prove the triangles are congruent

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Additive inverse of 2/8

balu736 [363]

Answer:

-2/8is it's answer

Step-by-step explanation:

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3 years ago

Evaluate g(n-7) if g(x) =x^2-5 / 3x

aleksandrvk [35]

Answer:

$g(n-7)=\frac{n^2-14n+44}{3n-21}$

Step-by-step explanation:

The given function is

$g(x)=\frac{x^2-5}{3x}$

To find g(n-7), we substitute x=n-7 to obtain;

$g(n-7)=\frac{(n-7)^2-5}{3(n-7)}$

Expand the parenthesis to obtain;

$g(n-7)=\frac{n^2-14n+49-5}{3n-21}$

Simplify:

$g(n-7)=\frac{n^2-14n+44}{3n-21}$

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4 years ago

The points (2, 100) and (4, 105) are found on a line.

Sophie [7]

I think its c

Step-by-step explanation:

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2 years ago

Write 12.6 as a mixed number with the fraction in simplest form

Naily [24]

Using your knowledge of place value the number is

12 6/10 which then reduces to

12 3/5

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3 years ago

An analyst tested the null hypothesis µ ≥ 30 against the alternative hypothesis that µ < 30. The analyst reported a p-value o

hoa [83]

Answer:

For significance levels lower than 0.07, the null hypothesis would be rejected.

Step-by-step explanation:

Decision regarding the null hypothesis:

The decision depends on the p-value of the test.

If the p-value of the test is less than the significance level, the null hypothesis is reject.

If the p-value of the test is more than the significance level, the null hypothesis is not reject.

The analyst reported a p-value of 0.07. For what significance level of will the null hypothesis would be rejected?

From the theory above, for significance levels lower than 0.07, the null hypothesis would be rejected.

8 0

3 years ago