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Lelu [443]
3 years ago
15

Can somebody pls answer this ASAP plsssssssssssssssssssssssssss​

Mathematics
1 answer:
34kurt3 years ago
4 0

Answer: D

Dependent variable is Distance.

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What are the square roots of 100? Check all that apply.
Helga [31]
There are three options which are the square roots of 100, and those are C. -10, D. 10, and F. |10|
C: (-10)^2 = -10 * -10 = 100 (- * - = +)
D: 10 * 10 = 100
F: |10| = 10, and 10 * 10 = 100 (these brackets make a negative number positive, and a positive number stays positive)
6 0
3 years ago
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How many minutes are there between 8:20 p.m. and 10:05 p.m.​
Fed [463]

Answer:

105 minutes.

Step-by-step explanation:

first you would subtract 60 by 20 to get 40 then your time would be at 9:00 so in order to get to 10:00 you would have 60 minutes which you would add the 40 to to get 100 minutes then add 5 to bring your time to 10:05 and your total number of minutes to 105

7 0
3 years ago
Find the equation of a line that contains the points (3,7) and (-6, 4). Write the equation in slope-intercept form, using
NikAS [45]

Answer:

y=\frac{1}{3} x+6

Step-by-step explanation:

(3,7)(-6,4)

Step 1. Find the slope (by using the slope-formula)

m = slope

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{4-7}{-6-3}

m=\frac{-3}{-9}

m=\frac{3}{9}

m=\frac{1}{3}

Step 2. Write the equation (using the slope and the points)

Here's how to do it:

Slope-intercept Formula y=mx+b whrere m = slope and b = y-intercept

Plug in the slope into the Slope-intercept Formula

y=\frac{1}{3} x+b

Find the y-intercept (b) by using a point and substituting their x and y values

y=\frac{1}{3} x+b

Point: (3, 7)

7=\frac{1}{3} (3)+b

7=1+b

b=7-1

b=6

Step 3. Write the equation in Slope-intercept form

y=mx+b

y=\frac{1}{3} x+6

3 0
2 years ago
The graph of F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x). If F(x)=x^2, which of th
vesna_86 [32]
To stretch it vertically, you'll need a coefficient greater than 1 in front of the x. If you want to flip the graph over the x axis that coefficient needs to be negative. So it can only be D
5 0
3 years ago
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Hellllllllllllllllllllllllllp
murzikaleks [220]

Answer:

\begin{cases}y=-5x+1\\y=5x-4 \end{cases}

Step-by-step explanation:

Slope-intercept form of a <u>linear equation</u>:

\boxed{y=mx+b}

where:

  • m is the slope.
  • b is the y-intercept (where the line crosses the y-axis).

<u>Slope formula</u>

\boxed{\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}}

<u>Equation 1</u>

<u />

Define two points on the line:

  • \textsf{Let }(x_1,y_1)=(-1, 6)
  • \textsf{Let }(x_2,y_2)=(0, 1)

<u>Substitute</u> the defined points into the slope formula:

\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1-6}{0-(-1)}=-5

From inspection of the graph, the line crosses the y-axis at y = 1 and so the y-intercept is 1.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

y=-5x+1

<u>Equation 2</u>

<u />

Define two points on the line:

  • \textsf{Let }(x_1,y_1)=(1, 1)
  • \textsf{Let }(x_2,y_2)=(0, -4)

<u>Substitute</u> the defined points into the slope formula:

\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-4-1}{0-1}=5

From inspection of the graph, the line crosses the y-axis at y = -4 and so the y-intercept is -4.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

y=5x-4

<u>Conclusion</u>

Therefore, the system of linear equations shown by the graph is:

\begin{cases}y=-5x+1\\y=5x-4 \end{cases}

Learn more about systems of linear equations here:

brainly.com/question/28164947

brainly.com/question/28093918

5 0
1 year ago
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