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aleksandrvk [35]
3 years ago
11

PLEASE HELP ME ASAP I AM BEGGING YOU. NO SPAM ANSWERS. Find the perimeter of the shaded regions below. Give your answer as a com

pletely simplified exact value in terms of (no approximations). The figures below are based on semicircles or quarter circles and problems b), c), and d) are involving portions of a square. ONLY FIND THE PERIMITER PLZ​
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!JUST THE PERIMETER PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Mathematics
2 answers:
satela [25.4K]3 years ago
5 0

Can you make a different question with an image attached?

Dafna11 [192]3 years ago
3 0
We need the picture to see the shaded regions
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What is the expected frequency of east campus and passed?
ser-zykov [4K]

The expected frequency of east campus and passed is C. 42 students

<h3>How to calculate the value?</h3>

The table for expected frequency is ,

East Campus West Campus Total

Passed (84*100)/22=42 (84*100)/200 =42 84

Failed (116*100)/200=58 (116*100)/22=58 116

Total 100 100 200

Passed = 84×100/200

= 42

Therefore, the expected frequency of East Campus and Passed is 42 students.

Learn more about frequency on:

brainly.com/question/254161

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3 0
1 year ago
What is the value of x
Softa [21]

Answer:46

Step-by-step explanation:

180-134

5 0
3 years ago
Read 2 more answers
10.
Crank
7.5 × 10-4

That's the scientific notation answer ^
5 0
3 years ago
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The table shows the number of minutes Garrett practiced his trombone each week in one month. Week Number of Minutes Practiced 1
vredina [299]

Answer:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The reason is because we assume that each week have the same weight and replacing we got:

\bar X= \frac{190+163+327+205}{4}= 221.25

And the best option would be:

D. 221.25

Step-by-step explanation:

For this case we have the following data given

Week       1       2         3       4

Minutes  190   163   327   205

For this case we can find the mean with the following formula:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The reason is because we assume that each week have the same weight and replacing we got:

\bar X= \frac{190+163+327+205}{4}= 221.25

And the best option would be:

D. 221.25

4 0
3 years ago
Sandy has 28 pencils and 72 erasers. She wants to make the greatest number of bags that have the same number of pencils and eras
aalyn [17]

Answer:

she can make a maximum of 4 bags.

peach bags containing 7 pencils and 18 erasers.

Step-by-step explanation:

find all the factors each numbers are divisible by:

28 => 1, 2, 4, 7, 14, 28

72 => 1, 2, 3, 4, 8, 9, 18, 24, 36, 72

choose the maximum common denominator.

7 0
3 years ago
Read 2 more answers
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