To solve this problem, we will need the standard kinematics equation
where
v0=initial velocity (positive upwards) m/s
t=time in seconds
a=acceleration due to gravity (positive upwards) = -9.81 m/ ²
Substituting values,
distance = 0 (when it falls back on earth)
v0=42 m/s
a=-9.81 (negative means towards earth, downwards)
factor and solve
=>
t=0 (beginning of launch), or
42-(1/2)*9.81t=0 => t=2*42/9.81=8.563 s.
Time to return = 8.6 seconds (to the nearest tenth of a second)
Answer:
A: The rate of change is 10% per year.
Step-by-step explanation:
The rate of change is simply the change in value divided by the change in time. In this case, the change in value is $1080 - $720 = $360, and the change in time is 12 years. Therefore, the rate of change is $360 / 12 years = $30 per year.
A: To find the rate in feet per minute, we can use the information given.
Every two minutes, the submarine dives 300 feet. So
.
In order to confirm that our rate is correct, we can use the second set of information given.
=
.
Since we know that the rate is 150 feet per minute, we can multiply it by any number of minutes and get the answer of how deep the submarine is. We can use a variable x to represent the number of minutes and y to represent the depth in feet.
There's our equation.
B: It would be more reasonable to use an equation with the rate feet per minute because it is more accurate since the time interval isn't too big.
Work backwards: 8/2=4. 5+x=4 which means 1+x=0. x=-1
Answer:
i dont know i just need points for more questions sorry
Step-by-step explanation: