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makvit [3.9K]
3 years ago
7

Hassan invested $900 in an account that pays 4.75% interest compounded annually. Assuming no deposits or withdrawals are made, f

ind how much money Hassan would have in the account 9 years after his initial investment. Round to the nearest tenth (if necessary).
show work please
Mathematics
2 answers:
Vsevolod [243]3 years ago
8 0
In 9 years he will have $1,366.6
mestny [16]3 years ago
6 0

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$900\\ r=rate\to 4.75\%\to \frac{4.75}{100}\dotfill &0.0475\\ n= \begin{array}{llll} \textit{times it compounds per year} \end{array}\dotfill &1\\ t=years\dotfill &9 \end{cases} \\\\\\ A=900\left(1+\frac{0.0475}{1}\right)^{1\cdot 9}\implies A=900(1.0475)^9\implies A\approx 1366.6

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Answer:

The number of students who scored more than 90 points is 750.

Step-by-step explanation:

Quartiles are statistical measures that the divide the data into four groups.

The first quartile (Q₁) indicates that 25% of the observation are less than or equal to Q₁.

The second quartile (Q₂) indicates that 50% of the observation are less than or equal to Q₂.

The third quartile (Q₃) indicates that 75% of the observation are less than or equal to Q₃.

It is provided that the first quartile is at 90 points.

That is, P (X ≤ 90) = 0.25.

The probability that a student scores more than 90 points is:

P (X > 90) = 1 - P (X ≤ 90)

                = 1 - 0.25

                = 0.75

The number of students who scored more than 90 points is: 1000 × 0.75 = 750.

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What is the value of x?
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The ans is choice D. since there nothing under 5x, imagine there is a 1 under. After that, you can simply cross multiply, so it would be 1(6+8x)= 2(5x). 6+8x= 10x now combine like terms so subtract 8x from both sides and divide 6 by 2 and you will get 3 
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PLEASE HELP!<br> Question in picture below!
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Answer:

x = 13/8

Step-by-step explanation:

sqrt(8x-4) +8 = 11

Subtract 8 from each side

sqrt(8x-4) +8-8 = 11-8

sqrt(8x-4) =3

Square each side

(sqrt(8x-4))^2 =3^2

8x-4 = 9

Add 4 to each side

8x-4+4 = 9+4

8x = 13

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3 years ago
the empire state building is 1250 feet tall. IF an object is thrown upward from the top of the building at an initial velocity o
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Answer:

Time for the object to get h(max)    s = 1.1875 sec

h (max)  = 1272.57 feet

Down time for the object to hit the ground   =  4.25 sec

Step-by-step explanation:

The relation

h(s)  =  -  16*s²  +  38* s  + 1250    (1)

Is equivalent to the equation for vertical shot

Δh = V(i)*t  -  1/2g*t²  (in this case we don´t have independent term since the shot is from ground level. We can see in (1), the independent term is 1250 feet ( the height of the empire state building), the starting point of the movement.

The description of the movement is:

V(s)  =  V(i)  - g*s     ⇒  V(s) = 38 - 32*s

At h(max)    V(s)  =  0      38/32  = s

So the maximum height is at  s = t = 1.1875 sec

The time for the object to pass for starting point is the same

t  =  1.1875 sec

h(max) is

h(max)  = - 16* (1.1875)² +  38 (1.1875) + 1250

h(max)  =  -  22,56  +  45.13  +  1250

h(max)  =  1272.57 feet

Time for the object to hit the ground is

h(s)  =  - 1250 feet

-1250  =  - 16 s² + 38*s  + 1250

-16s² +  38s  =  0

s ( -16s + 38 )  =  0

First solution for that second degree equation  is x = 0 which we dismiss

then  

( -16s + 38 )  =  0    ⇒ 16s   =  38     s  =  38/16

s =  2.375 sec    and  we have to add time between h (max) and to get to starting point  ( 1. 1875 sec)

total time is  = 2.375 + 1.875

Total time  =  4.25 sec

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3 years ago
A set of golf clubs that costs 7,000 dirhems are on sale for 20% off the regular price. What is the sale price of the
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Answer:

The answer is $1400.

Step-by-step explanation:

The main question here is, what is the sale price of the golf clubs?

1. Let's compute for 20% of 7,000.

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  • 20×70
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<h2>You should get 1400.</h2>

Hope this helps and if you could mark this as brainliest. Thanks!

7 0
3 years ago
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