Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Answer:
Step-by-step explanation:
We can use the distance formula derived from the Pythagorean theorem
D = 
the two points given are
(0, 3) and (-2, -3)

(please open my photo for reference as you read, I am a visual learner/explainer so it will make the most sense that way)
So the first thing you want to do is look at the exterior angle 130°. A straight line is 180°, and every Triangle's angular sum is 180°. How I think of it is that every straight line has a mini protractor on either side. It makes it a bit easier to understand.
180 - 130 = 50
You now know that two of the angles are 50°.
You now have two of the measurements for the triangle farthest to the left.
75° and 50°
75 + 50 = 125
180 - 125 = 55
a = 55°
Now that you have all the measurements for the first triangle, let's move onto the next one.
With two measurements for the second triangle, all you need to do is find their sum and subtract that from 180 and you will have the third measurement!
50 + 60 = 110
180 - 110 = 70
b = 70°
Finally, for the last triangle, you already have two of the measurements 60° and 85°.
85 + 60 = 145
180 - 145 = 35
c = 35°
Sorry if this explanation is a bit messy, it's hard to describe certain things without a letter or some kind of name to differentiate between them verbally.
I hope this helps! <3
Your answer would be 23.85 but I presume they rounded up so it would be 23.9
Answer:
42 mph
Step-by-step explanation:
From 2 p.m. to 6 p.m. 4 hours passed, so the truck and the motorcycle were on the road for 4 hours until they met.
Motorcycle in 4 hours at a constant speed of 45 mph travelled

The distance between the motorcycle and the truck is 348 miles, so the truck travelled

If x mph is truck's speed, then
