A1 = 9 × 1 - 6 = 3
A2 = 18 - 6 = 12
A3 = 27 - 6 = 21
A4 = 36 - 6 = 30.
Step-by-step explanation:
Σ ( 9n - 6 ) , n = 1
An = general term.
let Σ (An) = Σ (9n-6)
An = 9n-6
to determine the terms, plug in the value of n into the general term(An)
If you're asked for the 1st term then n = 1
if you're asked for the 2nd term then n = 2. and so forth.
To find the 1st 4 terms, just plug in 1 up to 4 into n bit by bit.
An = 9n - 6
A1 = 9 × 1 - 6 = 3
A2 = 18 - 6 = 12
A3 = 27 - 6 = 21
A4 = 36 - 6 = 30. done.
write the terms from 1 to 4 like this :
{ A1, A2, A3, A4 } = { 3, 12, 21, 30 }.
Answer:
1927 times
Step-by-step explanation:
To do this, you divide the second value by the first value.
This gives us 188,869 divided by 98, which equals around 1927.
Hope this helps.
X= 100 would be the answer
Let's use our largest amount (quarter) to see how many can fit evenly into 1.74.
- 1.74/0.25 = 6.96
- The most quarters that can fit into $1.74 is 6.
---Multiply $0.25 by 6 = $1.50
---Subtract $1.50 from $1.74 = $0.24
---We need to use the rest of the coins to fill up $0.24.
Now let's use our second largest amount (dime) to see how many can fit evenly into 0.24.
- 0.24/0.10 = 2.4
- The most dimes that can fit into $0.24 is 2.
---Multiply $0.10 by 2 = $0.20
---Subtract $0.20 from $0.24 = $0.04
No nickels can fit into $0.04, because they are worth $0.05.
We can use our least amount (pennies) to fill in the $0.04 remaining.
Your answer is 6 quarters, 2 dimes, and 4 pennies.
I think the answer is irrational
